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Stolb23 [73]
3 years ago
10

Someone please help me I’ll give out brainliest please dont answer if you don’t know

Mathematics
1 answer:
sasho [114]3 years ago
6 0

Answer:

$56.25

Step-by-step explanation:

3% of 750, then multiply by 2.5

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Which pair of funtions is not a pair of inverse functions? please help!!
antiseptic1488 [7]

Answer:

f(x)=\frac{x}{x+20} , g(x)=\frac{20x}{x-1}

Step-by-step explanation:

we know that

To find the inverse of a function, exchange variables x for y and y for x. Then clear the y-variable to get the inverse function.

we will proceed to verify each case to determine the solution of the problem

<u>case A)</u> f(x)=\frac{x+1}{6} , g(x)=6x-1

Find the inverse of f(x)

Let

y=f(x)

Exchange variables x for y and y for x

x=\frac{y+1}{6}

Isolate the variable y

6x=y+1

y=6x-1

Let

f^{-1}(x)=y

f^{-1}(x)=6x-1

therefore

f(x) and g(x) are inverse functions

<u>case B)</u> f(x)=\frac{x-4}{19} , g(x)=19x+4

Find the inverse of f(x)

Let

y=f(x)

Exchange variables x for y and y for x

x=\frac{y-4}{19}

Isolate the variable y

19x=y-4

y=19x+4

Let

f^{-1}(x)=y

f^{-1}(x)=19x+4

therefore

f(x) and g(x) are inverse functions

<u>case C)</u> f(x)=x^{5}, g(x)=\sqrt[5]{x}

Find the inverse of f(x)

Let

y=f(x)

Exchange variables x for y and y for x

x=y^{5}

Isolate the variable y

fifth root both members

y=\sqrt[5]{x}

Let

f^{-1}(x)=y

f^{-1}(x)=\sqrt[5]{x}

therefore

f(x) and g(x) are inverse functions

<u>case D)</u> f(x)=\frac{x}{x+20} , g(x)=\frac{20x}{x-1}

Find the inverse of f(x)

Let

y=f(x)

Exchange variables x for y and y for x

x=\frac{y}{y+20}

Isolate the variable y

x(y+20)=y

xy+20x=y

y-xy=20x

y(1-x)=20x

y=20x/(1-x)

Let

f^{-1}(x)=y

f^{-1}(x)=20x/(1-x)

\frac{20x}{1-x}\neq \frac{20x}{x-1}

therefore

f(x) and g(x) is not a pair of inverse functions

7 0
3 years ago
Read 2 more answers
Entre Celia y Quique suman 14€. Si Celia tuviera 1 €, tendría el doble de dinero que Quique.¿ Cuanto dinero tiene cada uno?
denpristay [2]

Answer:

La cantidad de dinero

Celia tiene = x = 9.33 €

Quique tiene = y = 4.67 €

Step-by-step explanation:

Representemos la cantidad de dinero

Celia tiene = x

Quique tiene = y

Entre Celia y Quique suman 14 €.

x + y = 14

x = 14 - y

Si Celia tuviera 1 euro, tendría el doble de dinero que Quique.

Por lo tanto,

x = 2 años

Nosotros sustituimos

2y + y = 14

3 años = 14

y = 14/3

y = 4.67 €

x = 14 € - y

x = 14 € - 4.67 €

x = 9.33 €

Por lo tanto,

La cantidad de dinero

Celia tiene = x = 9.33 €

Quique tiene = y = 4.67 €

7 0
3 years ago
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What number needs to be subtracted from both sides of the equation 40 = 25 + x in order to solve for x? HELP PLEASE!!!
dalvyx [7]

Answer:

Subtract 25 to both sides

6 0
3 years ago
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For which function is the domain -6 is less than or equal to x less than or equal to -1 not appropriate? A) y=x^2 B) y=2x C) y=
elena-s [515]

Answer: idk jus needed the points so im answering

3 0
3 years ago
P is the probability of a certain event. Which of the following indicates that P is certain to happen?
podryga [215]
Note for probability, if it will never happen the P = 0. If it must happen P = 1.

So certain to happen:

C. P=1

8 0
3 years ago
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