Answer:
a) H0:
H1:
b)
And the critical values with on each tail are:
c)
d) For this case since the critical value is not higher or lower than the critical values we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true deviation is not significantly different from 1.34
Step-by-step explanation:
Information provided
n = 10 sample size
s= 1.186 the sample deviation
the value that we want to test
represent the p value for the test
t represent the statistic (chi square test)
significance level
Part a
On this case we want to test if the true deviation is 1,34 or no, so the system of hypothesis are:
H0:
H1:
The statistic is given by:
Part b
The degrees of freedom are given by:
And the critical values with on each tail are:
Part c
Replacing the info we got:
Part d
For this case since the critical value is not higher or lower than the critical values we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true deviation is not significantly different from 1.34
Answer:
one solution
Step-by-step explanation:
because it's a gksbn smksidihdbd jaiaigsvs j
3/4 times n=1
remember that when you multiply 3/4 by 4/3 you get 12/12=1 so it simplifies
remember that you can do anything to an equation as long as you do it to both sides
3/4 ties n=1
multiply both sides by 4/3 to clar fraction
12/12 times n=4/3 times 1
1 times n=4/3
n=4/3
answer is n=4/3 or 1 and 1/3