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2 years ago

Hiiioo!! Can you please help me out with this!!! ❤️❤️:) (9)

Mathematics

1 answer:

Eduardwww [97]2 years ago

4 0

9514 1404 393

Answer:

segment SR
Given
segment PR
SSS postulate

Step-by-step explanation:

1. The only "Given" statement involving QR is ...

QR ≅ SR

2. You will notice that PQ ≅ PS is a Given statement.

3. The reflexive property says a segment is congruent to itself:

PR ≅ PR

4. All three sides of the triangles have been shown to be congruent. The appropriate choice for the postulate that shows congruence of the triangles is the SSS Postulate.

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I really need help i’m going to fail so answer if you can ! <3

Volgvan

Answer:

110

Step-by-step explanation:

you place 30 in the place of X, and it becomes 4×30-10. in PEMDAS, multiplication goes first and 4×30=120. 120-10=110

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3 years ago

A parallelogram has a base length of 9.3 inches and an area of 56.73 squared inches. Find the height of the parallelogram.

Studentka2010 [4]

Answer:

the answer is 6.1

Step-by-step explanation:

h= A over B (means you divide) and you get 6.1

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2 years ago

Read 2 more answers

What is 5 + 2x + 7 + 4x

Aneli [31]

Answer:

12+8x

Step-by-step explanation:

By adding together alike values, 5 and 7, and 2x and 4x, you get 12+8x.

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2 years ago

Which are the solutions of the quadratic equation? x2 = –5x – 3 –5, 0 StartFraction negative 5 minus StartRoot 13 EndRoot Over 2

boyakko [2]

<u>Given</u>:

The quadratic equation is $x^{2}=-5 x-3$

We need to determine the solutions of the quadratic equation.

<u>Solution</u>:

Let us solve the equation to determine the value of x.

Adding both sides of the equation by 5x and 3, we get;

$x^{2}+5 x+3=0$

The solution of the equation can be determined using quadratic formula.

Thus, we get;

$x=\frac{-5 \pm \sqrt{5^{2}-4 \cdot 1 \cdot 3}}{2 \cdot 1}$

$x=\frac{-5 \pm \sqrt{25-12}}{2 }$

$x=\frac{-5 \pm \sqrt{13}}{2 }$

Thus, the two roots of the equation are $x=\frac{-5 + \sqrt{13}}{2 }$ and $x=\frac{-5- \sqrt{13}}{2 }$

Hence, the solutions of the equation are $x=\frac{-5 + \sqrt{13}}{2 }$ and $x=\frac{-5- \sqrt{13}}{2 }$

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3 years ago

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A rectangle has an area of 240 square meters and a width of 15 meters.

fredd [130]

Area is found by taking the length time width or A=lw

240=L x 15 divide both sides by 15

Length = 16 meters

3 0

3 years ago