You would first look at the tens place numbers; 10 and 30. and add them together making 40. after that you'd take the ones places and add them together; 7 and 8. add those together and you'd get 15. to finish you just need to add the two numbers together 40 and 15.
<span>Winning Probablity = 0.2, hence Losing Probability = 0.8
Probablity of winning atmost one time, that means win one and lose four times or lose all the times. So p(W1 or W0) = p (W1) + p(W0)
Winning once W1 is equal to L4, winning zero times is losing 5 times.
p(W1) = p(W1&L4) and this happens 5 times; p(W0) = p(L5);
p (W1) + p(W0) = p(L4) + p(L5)
p(L4) + p(L5) = (5 x 0.2 x 0.8^4) + (0.8^5) => 0.8^4 + 0.8^5
p(W1 or W0) = 0.4096 + 0.32768 = 0.7373</span>
This question is gonna need the picture to go with it
Robot 1- W = 20(3m) W= 60Nm
Robot 2- W= 30N (3m), W = 90Nm
Robot 3- W= 10N(2m), W= 20Nm
Robot 4- W= 30N(2m), W= 60Nm
Robot 2 did the most work, Robot 3 did the least amount of work and Robots, 1 and 4 did an equal amount of work
