Answer:
36¢ per pound
Step-by-step explanation:
In 1995, the price per pound was ...
($24.7 million)/(15 million lb) = $1.6467/lb
In 2000, the price per pound was ...
($31,297,583)/(15,616,728 lb) = $2.0041/lb
The difference was ...
$2.0041 -1.6467 = $0.3574 ≈ 36¢ . . . per pound
_____
In a calculation such as this, you want to keep enough significant digits so that you can appropriately round the final answer. Here, the result would be different if intermediate values were rounded to whole cents.
Answer:
21
Step-by-step explanation:
PEMDAS:
Parenthesis
Exponent
Multiplication and Division
Addition and Subtraction
21-3+3
18+3
21
Hope this helps!
I = PRT/100
100I = PRT
P= 100I÷RT
P = 100I/RT
Answer:
C. (-1, 3)
Step-by-step explanation:
Label the 2 equations:
5y= 7x +22 -----(1)
x= -6y +17 -----(2)
Substitute (2) into (1):
5y= 7(-6y +17) +22
5y= -42y +119 +22 <em>(</em><em>Expand</em><em> </em><em>bracket</em><em>)</em>
5y= -42y +141 <em>(</em><em>Simplify</em><em>)</em>
42y +5y= 141 <em>(</em><em>+</em><em>42y</em><em> </em><em>on</em><em> </em><em>both</em><em> </em><em>sides</em><em>)</em>
47y= 141
y= 141 ÷47 <em>(</em><em>÷</em><em>4</em><em>7</em><em> </em><em>on</em><em> </em><em>both</em><em> </em><em>sides</em><em>)</em>
y= 3
Substitute y= 3 into (2):
x= -6(3) +17
x= -18 +17
x= -1
Thus, the solution is (-1, 3).
Answer:
Step-by-step explanation:
A) From the order of the exercise we already know that the intersection points lies on the Y-axis, so its coordinates are P(0;y;0). In order to find it, we only need to substitute the equation 4x+4z=0 into the equation 4x+3y+4z=1. Then,
1=4x+3y+4z = 3y + (4x+4z)= 3y+0.
From the expression above it is easy to obtain that y=1/3, and the intersection point is P(0;1/3;0).
B) To obtain the parallel vector to both planes we use the cross product of the normal vector of the planes.
![\left[\begin{array}{ccc}i&j&k\\4&3&4\\4&0&4\end{array}\right] = 12i-0j+12k](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Di%26j%26k%5C%5C4%263%264%5C%5C4%260%264%5Cend%7Barray%7D%5Cright%5D%20%3D%2012i-0j%2B12k)
As we want a unit vector, we must calculate the modulus of u:
.
Thus, the wanted vector is 
. Therefore,
.
C) In order to obtain the vector equation of the intersection line of both planes, we just need to put together the above results.
where 
is a real number.
