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Fed [463]
2 years ago
11

The total price of a shirt and a cap is $11. If the price of the shirt was doubled and the price of the cap was three times its

original price, the total price of a shirt and a cap would be $25. The following system of equations models this scenario:
x + y = 11

2x + 3y = 25


What is the price of each shirt and cap?



Price of a shirt is $9, and price of a cap is $2.



Price of a shirt is $10, and price of a cap is $1.



Price of a shirt is $8, and price of a cap is $3.



Price of a shirt is $7, and price of a cap is $4.
Mathematics
1 answer:
shusha [124]2 years ago
4 0

Answer:

the shirt is 8 dollars and the cap is 3

Step-by-step explanation:

This is because 8 times 2 is 16 which is the new price of the shirt then 3 times 3 is 9 which would be the new cap price and 16 plus 9 is 25

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The equations x+5x=16
and x+5x+25=16
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If 4r+3trs-3u+2=12s+r-1, then t =
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Keith has 40-pound bags of mulch in his truck that weigh a total of 3600 pounds. His Owner’s Manual lists the truck’s capacity a
kiruha [24]

Answer:

Keith must remove 90-75 = 15 bags in order to meet the weight requirements

Step-by-step explanation:

This problem can be solved by consecutive rules of three problem.

Rule of three problem:

In a rule of three problem, the first step is identifying the measures and how they are related, if their relationship is direct of inverse.

When the relationship between the measures is direct, as the value of one measure increases, the value of the other measure is going to increase too. In this case, the rule of three is a cross multiplication

When the relationship between the measures is inverse, as the value of one measure increases, the value of the other measure will decrease. In this case, the rule of three is a line multiplication.

In this problem, the measures are:

- The number of bags

- The total weight

As the number of bags increases, so do the total weight. So, the relationship between the measures is direct.

To know how many bags does Keith need to remove in order to meet the weight requirements, we first need to know how many bags are in the truck currently.

The problem states that each bag weighs 40 pounds and the weight of the truck is 3600 pounds, so:

1 bag - 40 pounds

x bags - 3600 pounds

40x = 3600

x = \frac{3600}{40}

x = 90.

Keith currently has 90 bags in the truck.

Now, we have to know how much bags he can have in the truck, that is, 3000 pounds worth of bags. So:

1 bag - 40 pounds

x bags - 3000 pounds

40x = 3000

x = \frac{3000}{40}

x = 75.

The truck's capacity is at most 75 bags.

So, Keith must remove 90-75 = 15 bags in order to meet the weight requirements

7 0
3 years ago
55 Attes Sosis an
SOVA2 [1]

Answer:

A = $3801

Step-by-step explanation:

P=3900

r=2.1

n=1

t=10

A=3900\left(1+\frac{2.1\%\:}{1}\right)^{1\cdot \:10}

2.1\%\: = 0.021

A=3900\left(1+0.021\right)^{1\cdot \:10}

A=3900\cdot \:1.021^{10}

A=3900\cdot \:1.23099\dots

A=4800.89301\dots

A = $3801

6 0
2 years ago
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