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skelet666 [1.2K]
3 years ago
10

Help I will give brainliest if you do everything

Mathematics
1 answer:
DaniilM [7]3 years ago
4 0
5a) 2x + 16

5b) The y intercept=16 represents the order cost excluding the prints themself.


Explanation: X = the # of prints ordered and each print costs $2 to add to the order.


6a) 7x + 5

6b) 47 inches
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Suppose a random variable, x, arises from a binomial experiment. If n = 25, and p = 0.85, find the variance. Round answer to 4 d
Tamiku [17]

Answer:

<u><em>a) P(X=1) = 0.302526</em></u>

<u><em>b) P(X=5) = 0.010206</em></u>

<u><em>c) P(X=3) = 0.18522</em></u>

<u><em>d) P(X≤3) = 0.92953</em></u>

<u><em>e) P(X≥5) = 0.010935</em></u>

<u><em>f) P(X≤4) = 0.989065</em></u>

<u><em></em></u>

<u><em></em></u>

<u><em>If helpful, please mark as brainliest! =)</em></u>

8 0
3 years ago
Find the equation of the line parallel to y=3x+5 that passes through (0,4) y=3x+4
Contact [7]
Y=3x+4 is the line parallel to y=3x+5
7 0
3 years ago
If the length of a rectangular field is twice the width and the perimeter is 24. Write an equation that an be used to solve for
Sedbober [7]
If we use the width as x we have 2x with both widths and 4x with both lengths. So 6x=24 and x=4. So length is 8 and width is 4.
7 0
4 years ago
The volume of a cone varies jointly as the height of the cone and the area of the base. The volume of a cone with height 30 cent
irina [24]

Answer:

V₂=28cm³

Step-by-step explanation:

<u>Way 1</u>

The volume of a cone is V=\frac{\pi r^{2}h}{3},  and  h₁ = 30 cm but the base (Ba₁) is 14 cm², so

V=\frac{Ba.h}{3}, where Ba= Base area

if h₂=7cm and Ba₂=12cm² then

V_{1} =\frac{12cm^{2}.7cm}{3}=28cm^{3}

<u>Way2</u>

If the volume of a cone varies jointly as the height of the cone and the area of the base, then we must find the relationship between the bases and heights of the cones

Ba₁*h₁ = 30cm*14cm² = 420cm³

Ba²*h²=   7cm*12cm² =   84cm³

420/84 = 5; ratio = 5 also

V₂=V₁/5 ⇒ V₂=140cm³/5 = 28cm³

8 0
3 years ago
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The population of the United States was about 280 million in 2000 and about 310 million in 2010 . What was the annual rate of ch
storchak [24]
<span>In order to solve this you would need to take the difference in population and then divide by the difference of the number of years that have passed. So first we figure that there is a 30 million difference in population over the course of 10 years. So you would take 30 and divide by 10. Your problem would then appear as this 30/10=3 ... ( I removed all unnecessary zeros from the equation to simplify it). The answer is an annual rate of 3 million people per year (after adding back all necessary zeros to get back to the proper population number in the millions).</span>
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