we are given that out of 100 light bulbs, 7 of them were defective. We can assume that out of every 100 lightbulbs, 7 of them will be defective.
we can write this as a ratio of defective lightbulbs to total
7:100
we want to see how many defective there are when we have 3000 bulbs, to do this we can multiply both numbers by 30
7 * 30 = 210
100 * 30 = 3,000
our new ratio is now
210:3,000
so we are now able to say that in a lot of 3,000 lightbulbs, there would be 210 defective bulbs.
hope this helped!
I do not even know man I’m just wandering because I want the points sorry
Answer:
The z-score is
The length of days is not unusual
Step-by-step explanation:
From the question we are told that
The population mean is
The standard deviation is
The value considered is
The z-score is mathematically represented as
Now given that the z-score is not greater than 3 then we can say that the length of days is not unusual
(reference khan academy)
Answer:
C) 9
Step-by-step explanation:
54 = 2 x 3 x 3 x 3
81 = 3 x 3 x 3 x 3
common factor of 54 and 81 = 3 x 3 = 9
Answer: 9
First distribute -8 to all terms within the parenthesis.
-8(m + 7) = -8m - 56
Next, isolate the m. Add 8m to both sides, and subtract -53 from both sides.
-8m (+8m) + 53 (-53) = -8m (+8m) - 56 -53
-8m + 8m = -56 - 53
Simplify
0 ≠ - 109
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This equation cannot be solved, and is undefined.
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hope this helps