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Kazeer [188]
3 years ago
9

Ricardo has 2020 coins, some of which are pennies (1-сent coins) and the rest of which are

Mathematics
1 answer:
r-ruslan [8.4K]3 years ago
6 0

Answer:

B

Step-by-step explanation:

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Solve the equation on the<br> interval [0, 2π).<br> √2 cos x - 1 = 0
jek_recluse [69]

Answer:

Step-by-step explanation:

\sqrt{2} cos x-1=0\\cos x=\frac{1}{\sqrt{2} } =cos (\frac{\pi }{4} ),cos (2\pi -\frac{\pi }{4} )\\cos x=cos(2n\pi +\frac{\pi }{4} ),cos(2n\pi +\frac{7\pi }{4} )\\x=2n\pi +\frac{\pi }{4} ,2n\pi +\frac{7\pi }{4} \\n=0\\x=\frac{\pi }{4} ,\frac{7\pi }{4}

8 0
2 years ago
Two cars are traveling in the same direction. the first car is going 40 mph and the second car is going 55 mph. the first car le
jarptica [38.1K]
I hope this helps you




distance=speed×time



first cars time t




second cars time t+3



same distance


distance=55.t


distance=40. (t+3)



55t=40 (t+3)



55t-40t=120


15t=120


t=8


t+3=11
4 0
3 years ago
Madison deposited $18 in a savings account that earns 2.5% simple interest. Which graph represent this scenario
Dmitriy789 [7]
The answer is 7.20 because $18 divided by 2.5% is 7.20
8 0
3 years ago
Read 2 more answers
Given z1 = 2 +StartRoot 3 EndRoot i and z2 = 1 – StartRoot 3 EndRoot i, what is the sum of z1 and z2?
Fofino [41]

Answer:

z1 + z2 = 3

Step-by-step explanation:

Since we are given z1 = 2 + √(3)i and z2 = 1 – √(3)i. The sum of z1 + z2 would be:

(2 + √(3)i) + (1 – √(3)i) = 2 + √(3)i + 1 – √(3)i = 2 + 1 + √(3)i – √(3)i = 3

Hence, z1 + z2 = 3.

8 0
3 years ago
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FIND THE GCF. Mathematics
Rom4ik [11]

The G.C.F of the given algebraic expression is; ⁴⁹/₆a xy

<h3>What is the G.C.F (Greatest Common Factor)?</h3>

The greatest common factor (GCF or GCD or HCF) of a set of whole numbers is the largest positive integer that divides evenly into all numbers with zero remainder. For example, for the set of numbers 18, 30 and 42 the GCF = 6.

We are given the algebraic expression;

(3 x y * 4x²y * ¹/₁ * 5x³y ^ z * 4)7a * 1/1 * 7*6

Expanding this further gives;

⁴⁹/₆a((3xy * 4x²y * 20x³y ^ z )

Now, the GCF of the terms inside the bracket would be x y. Thus, expanding the GCF  we have;

⁴⁹/₆a xy((3 * 4x * 20x²y^(z - 1))

Read more about G.C.F at; brainly.com/question/219464

#SPJ1

5 0
2 years ago
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