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aev [14]
3 years ago
9

How to solve 2x-8y=16

Mathematics
1 answer:
Darina [25.2K]3 years ago
3 0
The answer of your question is x - 4 y=8
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The graph represents the height of a ball after being thrown versus time. Which statement is true? A. The ball attains a maximum
Rama09 [41]

The statement which is true about the thrown ball is that A. The ball attains a maximum height of 70 meters at 4 seconds

<h3>What is a Maximum Height?</h3>

This refers to the highest vertical projectile that an object can attain when acted upon by an external force.

Given the attached diagram that shows the graph of the projectile of the ball, we can observe that its maximum height before it began to fall is 70 meters at 4 seconds based on the values on the x and y-axis.

Read more about maximum height here:

brainly.com/question/12446886

<h3>#SPJ1</h3>

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1 year ago
Is the following a function ?
Softa [21]

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yes

Step-by-step explanation:

7 0
2 years ago
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What is bigger:<br> 7/8<br> Or 3/4?
Aleks04 [339]

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7/8

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multiply 3/4 by 2/2 to get 6/8

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2 years ago
(Only need 17) plz help geometry will mark brainliest plz show work
Gre4nikov [31]

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143

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3 years ago
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Use cylindrical coordinates. find the volume of the solid that lies within both the cylinder x2 y2 = 9 and the sphere x2 y2 z2 =
marissa [1.9K]
In Cartesian coordinates, the region is given by -3\le x\le3, -\sqrt{9-x^2}\le y\le\sqrt{9-x^2}, and -\sqrt{16-x^2-y^2}\le z\le\sqrt{16-x^2-y^2}. Converting to cylindrical coordinates, using

\begin{cases}\mathbf x(r,\theta,\zeta)=r\cos\theta\\\mathbf y(r,\theta,\zeta)=r\sin\theta\\\mathbf z(r,\theta,\zeta)=\zeta\end{cases}

we get a Jacobian determinant of r, and the region is given in cylindrical coordinates by 0\le\theta\le2\pi, 0\le r\le3, and -\sqrt{16-r^2}\le z\le\sqrt{16-r^2}.

The volume is then

\displaystyle\int_{\theta=0}^{\theta=2\pi}\int_{r=0}^{r=3}\int_{z=-\sqrt{16-r^2}}^{z=\sqrt{16-r^2}}r\,\mathrm dz\,\mathrm dr\,\mathrm d\theta=\dfrac{4(64-7\sqrt7)\pi}3
6 0
2 years ago
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