<span>-3(1+6r)=14-r
-3 - 18r = 14 - r ...expand by using distributive property
-3 -17r = 14 ...add (r) to both sides
-17r = 17 ...add (3) to both sides
r = -1 ....divide both sides by (-17)</span>
Using the probability and odds concepts, it is found that the odds against it containing a number greater than or equal to 7 is
.
- A probability is the <u>number of desired outcomes divided by the number of total outcomes</u>.
- An odd is the <u>number of desired outcomes divided by the number of non-desired outcomes</u>.
In the rack, there are 15 balls, numbered from 1 to 15. Of those, <u>6 are less than 7</u>(against it containing a number greater than or equal to 7 is equivalent to it containing a number less than 7), thus:
- There are 6 desired outcomes.
- There are 9 non-desired outcomes.
The odd is:

The odds against it containing a number greater than or equal to 7 is
.
A similar problem is given at brainly.com/question/21094006
Y: x-1 that is the answer. I think so.