HELPP MEE ANSEERRR PLSSSS
2 answers:
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Answer:
y = 3x +4
Step-by-step explanation:
The equation for the parallel line will have the same x- and y-coefficients, but a different constant. You can put the given point values into the equation to see what the constant needs to be:
y = 3x + b
10 = 3·2 + b . . . . . . substitute x=2, y=10
4 = b . . . . . . . . . . . . subtract 6
The equation of the line is ...
y = 3x +4
Answer:
Given System of equation:
x-y =6 .....,[1]
2x-3z = 16 ......[2]
2y+z = 4 .......[3]
Rewrite the equation [1] as
y = x - 6 .......[4]
Substitute the value of [4] in [3], we get
Using distributive property on LHS ( i.e, )
then, we have
2x - 12 +z =4
Add 12 to both sides of an equation:
2x-12+z+12=4+12
Simplify:
2x +z = 16 .......[5]
On substituting equation [2] in [5] we get;
2x+z=2x -3z
or
z = -3z
Add 3z both sides of an equation:
z+3z = -3z+3z
4z = 0
Simplify:
z = 0
Substitute the value of z = 0 in [2] to solve for x;
or
2x = 16
Divide by 2 both sides of an equation:
Simplify:
x= 8
Substitute the value of x =8 in equation [4] to solve for y;
y = 8-6 = 2
or
y = 2
Therefore, the solution for the given system of equation is; x = 8 , y = 2 and z =0