Answer:
Displacement
Step-by-step explanation:
hope this helps !
Option D is correct. The required compatible number is 480 ÷ 60 = 8
Compatible numbers are numbers that have a close approximate to a given value
Given the expression 488 ÷ 62
The compatible number for 488 is 480
The compatible number for 62 is 60
Using these compatible numbers to solve the expression will give:
488 ÷ 62
= 480 ÷ 60
= 480/60
= 48/6
= 8
Hence the correct option will be 480 ÷ 60 = 8
Learn more here: brainly.com/question/22595072
In this situation, there are 2 separate terms (parts of the story). The first part is the information about the coupon that applies to the daily rate of $40. You will represent this as 0.75 (for the 75% that you will be paying) x 40. (The other part of this story is that you are paying $0.15 per mile which is represented as 0.15m. You need to put these together to get 0.75(40) + 0.15m. The 0.25 times 40 can be simplified to say 30, so write it as $30 + $0.15m.
Answer: (E) Not necessarily, because this wasn't an experiment
Step-by-step explanation:
As much as the results would suggest that the fast-paced music was responsible for the faster finishing time, this conclusion cannot be authoritatively made because this was not technically an experiment but rather a test to satisfy curiosity.
An experiment is planned and is scientific. It has more stringent requirements that ensure causation that Roshanda did not meet before she engaged in this trial so we cannot say for a fact that her findings are objective.
Below is the solution, I hope it helps.
<span>i) tan(70) - tan(50) = tan(60 + 10) - tan(60 - 10)
= {tan(60) + tan(10)}/{1 - tan(60)*tan(10)} - {tan(60) - tan(10)}/{1 + tan(10)*tan(60)}
ii) Taking LCM & simplifying with applying tan(60) = √3, the above simplifies to:
= 8*tan(10)/{1 - 3*tan²(10)}
iii) So tan(70) - tan(50) + tan(10) = 8*tan(10)/{1 - 3*tan²(10)} + tan(10)
= [8*tan(10) + tan(10) - 3*tan³(10)]/{1 - 3*tan²(10)}
= [9*tan(10) - 3*tan³(10)]/{1 - 3*tan²(10)}
= 3 [3*tan(10) - tan³(10)]/{1 - 3*tan²(10)}
= 3*tan(30) = 3*(1/√3) = √3 [Proved]
[Since tan(3A) = {3*tan(A) - tan³(A)}/{1 - 3*tan²(A)},
{3*tan(10) - tan³(10)}/{1 - 3*tan²(10)} = tan(3*10) = tan(30)]</span>
