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photoshop1234 [79]
3 years ago
9

If my usb could unlock my computer with a tool then could i be able to open it using ip unlock

Computers and Technology
1 answer:
LUCKY_DIMON [66]3 years ago
8 0

Answer:

no it can not

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What do you want to skip in brainly? There isn't anything to skip that I can think of.

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Which of these methods can you use to insert a new row in a worksheet?
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I think It should be B

Explanation:

If wrong so please sorry

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An audiophile is a person who _______.
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An audiophile is a person who is enthusiastic about high-fidelity sound reproduction.
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Read 2 more answers
Write a program whose input is two integers. Output the first integer and subsequent increments of 10 as long as the value is le
Lubov Fominskaja [6]

Answer:

import java.util.Scanner;

public class TestClock {

   public static void main(String[] args) {

       Scanner in = new Scanner(System.in);

       System.out.println("Enter two integer numbers");

       int num1 = in.nextInt();

       int num2 = in.nextInt();

       int newSum=num1+10;

       System.out.println("The first number is "+num1);

       do{

          System.out.println(newSum);

          newSum +=10;

       }while (newSum <=num2);

   }

}

Explanation:

Using Java Programming language

  1. Prompt user for the two inputs and save them as num1 and num2(Using the scanner class)
  2. Create a new Variable newSum = num1+10
  3. Create a do...while loop to continually print the value of newSum, and increment it by 10 while it is less or equal to num2
3 0
3 years ago
Write a java program to read elements in an array from user and count total number of duplicate elements in array.
Anna11 [10]

Answer:

Explanation:

The following code is written in Java and is a function/method that takes in an int array as a parameter. The type of array can be changed. The function then creates a counter and loops through each element in the array comparing each one, whenever one element is found to be a duplicate it increases the counter by 1 and moves on to the next element in the array. Finally, it prints out the number of duplicates.

public static int countDuplicate (int[] arr) {

               int count = 0;

               for(int i = 0; i < arr.length; i++) {

                       for(int j = i + 1; j < arr.length; j++) {

                               if(arr[i] == arr[j])

                                       count++;

                       }

               }

               return count;

       }

8 0
3 years ago
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