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9966 [12]
2 years ago
5

If a company saw an online photo of you playing basketball, it might try to sell

Computers and Technology
1 answer:
Ivahew [28]2 years ago
7 0

Answer:

C. high-top sneakers

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A computer retail store has 15 personal computers in stock. A buyer wants to purchase 3 of them. Unknown to either the retail st
Dima020 [189]

Answer:

a. 1365 ways

b. Probability = 0.4096

c. Probability = 0.5904

Explanation:

Given

PCs = 15

Purchase = 3

Solving (a): Ways to select 4 computers out of 15, we make use of Combination formula as follows;

^nC_r = \frac{n!}{(n-r)!r!}

Where n = 15\ and\ r = 4

^{15}C_4 = \frac{15!}{(15-4)!4!}

^{15}C_4 = \frac{15!}{11!4!}

^{15}C_4 = \frac{15 * 14 * 13 * 12 * 11!}{11! * 4 * 3 * 2 * 1}

^{15}C_4 = \frac{15 * 14 * 13 * 12}{4 * 3 * 2 * 1}

^{15}C_4 = \frac{32760}{24}

^{15}C_4 = 1365

<em>Hence, there are 1365 ways </em>

Solving (b): The probability that exactly 1 will be defective (from the selected 4)

First, we calculate the probability of a PC being defective (p) and probability of a PC not being defective (q)

<em>From the given parameters; 3 out of 15 is detective;</em>

So;

p = 3/15

p = 0.2

q = 1 - p

q = 1 - 0.2

q = 0.8

Solving further using binomial;

(p + q)^n = p^n + ^nC_1p^{n-1}q + ^nC_2p^{n-2}q^2 + .....+q^n

Where n = 4

For the probability that exactly 1 out of 4 will be defective, we make use of

Probability =  ^nC_3pq^3

Substitute 4 for n, 0.2 for p and 0.8 for q

Probability =  ^4C_3 * 0.2 * 0.8^3

Probability =  \frac{4!}{3!1!} * 0.2 * 0.8^3

Probability = 4 * 0.2 * 0.8^3

Probability = 0.4096

Solving (c): Probability that at least one is defective;

In probability, opposite probability sums to 1;

Hence;

<em>Probability that at least one is defective + Probability that at none is defective = 1</em>

Probability that none is defective is calculated as thus;

Probability =  q^n

Substitute 4 for n and 0.8 for q

Probability =  0.8^4

Probability = 0.4096

Substitute 0.4096 for Probability that at none is defective

Probability that at least one is defective + 0.4096= 1

Collect Like Terms

Probability = 1 - 0.4096

Probability = 0.5904

8 0
2 years ago
A technician is troubleshooting a Windows system in which an application works properly when the computer is booted in Safe Mode
sweet-ann [11.9K]

Answer:

yoooo nba BAD BAD

Explanation:

3 0
3 years ago
Develop a command sequence would you use to alter the amount of space between the text in a text box and the text box border?.
yanalaym [24]

The use of the Line and Paragraph Spacing command can  help one to alter the amount of space between the text in a text box and the text box border.

<h3>Which command changes line spacing?</h3>

When one click on Home tab, one should click the Line and Paragraph Spacing command, and when one has select the line spacing that one needs, the selected line spacing will alter in the document.

Note that the use of the Line and Paragraph Spacing command can  help one to alter the amount of space between the text in a text box and the text box border.

Learn more about command sequence from

brainly.com/question/13258375

#SPJ1

8 0
2 years ago
The user will input a three digit number
zlopas [31]

import java.util.Scanner;

public class U1_L5_Activity_One {

public static void main(String[] args) {

Scanner scan = new Scanner(System.in);

System.out.print("Please enter a two digit number: ");

int x = scan.nextInt();

System.out.println("Here are the digits:");

System.out.println(x/100);

System.out.println((x/10)%10); <em>//Just divide the result by 10 and find the remainder</em>

System.out.println(x%10);  

}

}

<em>//Or, you can do that way:</em>

<em />

import java.util.Scanner;

 

public class U1_L5_Activity_One {

public static void main(String[] args) {

Scanner scan = new Scanner(System.in);

System.out.print("Please enter a two digit number: ");

String[] x = scan.nextLine().split(""); <em>//We need it to be a string array, to split the values after "", that is, after each symbol(number)</em>

System.out.println("Here are the digits:");

for(int i = 0; i<x.length; i++) {

          System.out.println(Integer.parseInt(x[i])); <em>//Converting the string into int, as you want</em>

      }  

}

}

5 0
2 years ago
__________ is a network project that preceded the internet.
suter [353]
Arpanet. I think is the answer.
8 0
3 years ago
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