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yuradex [85]
3 years ago
15

HELPPPPP!!!!!!!!

Mathematics
1 answer:
Vlad1618 [11]3 years ago
8 0
The circumcenter of a triangle is the point in the plane equidistant from the three vertices of the triangle. so I believe it is A. True..
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Brad and Wes are building a tree house.They cut a 12 1/2 foot piece of wood into 5 equally sized pieces.How long is each piece o
inessss [21]
Answer=C 2 1/2

(12 1/2)÷5=2 1/2

or

12.5/5=2.5=2 1/2
7 0
3 years ago
What is the solution to the system of equations?
frez [133]
(-19,55) x is equal to -19 and y is equal to 55
4 0
3 years ago
Read 2 more answers
Solve for all values of x by factoring.<br> x^2 + 4x – 30 = -3x
vichka [17]

Answer:

{x}^{2}  + 4x - 30 =  - 3x \\{x}^{2}  + 7x - 30 = 0 \\  {x}^{2}  - 3x + 10x - 30 = 0 \\ x(x - 3) + 10(x - 3) = 0 \\ (x - 3)(x + 10) = 0 \\  \boxed{x = 3} \\  \boxed{x =  - 10}

<h3><em><u>x=3 or x=-10</u></em> is the right answer.</h3>

7 0
3 years ago
Para reunir dinero para su gira de estudios , los alumnos de un curso deciden vender números de una rifa que se encuentran numer
QveST [7]

Respuesta:

0.53

Explicación:

Para calcular la posibilidad del evento A: "ganar la rifa comprando todos los números múltiplos de 3 o 5", debemos usar la siguiente fórmula.

P(A) = casos favorables / casos posibles

Evaluemos primero todos los casos que son múltiplos de 3, entre 1 y 100: 3, 6, 9, 12, 15, 18, 21, 24, 27, 30, 33, 36, 39, 42, 45, 48, 51, 54, 57, 60, 63, 66, 69, 72, 75, 78, 81, 84, 87, 90, 93, 96, 99. En total son 33.

Ahora, evaluemos todos los casos que son múltiplos de 3, entre 1 y 100: 5, 10, 15, 20, 25, 30, 35, 40, 45, 50, 55, 60, 65, 70, 75, 80, 85, 90, 95, 100. En total son 20.

El número total de casos favorables es 33 + 20 = 53.

El número de casos posibles es el total de números de 1 a 100, es decir 100.

Luego P(A) = 53/100 = 0.53.

7 0
3 years ago
Plot the point. (5,0)
Svet_ta [14]
Is there a plot?? How do I know where each point is??
5 0
3 years ago
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