1) In a random sample of 150 out-patient records it was noted that 25 of the

Mathematics

1 answer:

Leno4ka [110]3 years ago

7 0

Answer:

Step-by-step explanation:

13% of 150 =19.5 which is less that 25 so it mst be greater than 13%

Hope this helps ;)

You might be interested in

Bill has enough money to buy no more than 1/2 pound of cheese. How much cheese could he buy?

andriy [413]

1/2 I guess I don't think you typed in the question correctly. Not trying to be mean.

3 0

3 years ago

Find the quotient Write the remainder as a fraction 89,420÷27

goldfiish [28.3K]

3311.85185.... is the quotient. The fraction is 3311 23/27

3 0

3 years ago

Read 2 more answers

A teacher was interested in knowing the amount of physical activity that his students were engaged in daily. He randomly sampled

klasskru [66]

Answer:

The standard error of the mean is 4.5.

Step-by-step explanation:

As we don't know the standard deviation of the population, we can estimate the standard error of the mean from the standard deviation of the sample as:

$\sigma_{\bar{x}}\approx\frac{s}{\sqrt{n}}$

The sample is [30mins, 40 mins, 60 mins, 80 mins, 20 mins, 85 mins]. The size of the sample is n=6.

The mean of the sample is:

$\bar{x}=\frac{1}n} \sum x_i =\frac{30+40+60+80+20+85}{6}=52.5$

The standard deviation of the sample is calculated as:

$s=\sqrt{\frac{1}{n-1}\sum (x_i-\bar x)^2} \\\\ s=\sqrt{\frac{1}{5}\cdot ((30-52.5)^2+(40-52.5)^2+(60-52.5)^2+(80-52.5)^2+(20-52.5)^2+(85-52.5)^2}\\\\s=\sqrt{\frac{1}{5} *3587.5}=\sqrt{717.5}=26.8$