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Keith_Richards [23]
3 years ago
7

Given f(x) = x^2 - 5x, find f(x-3)

Mathematics
1 answer:
Hoochie [10]3 years ago
3 0

Answer:

f(x-3)= x^2 -11x +24

Step-by-step explanation:

We want to find an equivalent expression for f(x-3)

To do this, we can simply substitute every 'x' variable in f(x) by 'x-3'

Therefore f(x-3)= (x-3)^2 -5*(x-3)

Lets re arrange the expression by grouping terms.

f(x-3)=x^2 - 6x +9 -5x + 15

f(x-3)= x^2 -11x +24

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PLEASE HELPPPPPPPPPP
Sauron [17]

Answer:

167/346 or 0.483

Step-by-step explanation:

From the question given above, the following data were obtained:

Number of Tails (T) = 167

Number of Heads (H) = 179

Probability of tail, P(T) =?

Next, we shall determine total outcome. This can be obtained as follow:

Number of Tails (T) = 167

Number of Heads (H) = 179

Total outcome (S) =?

S = T + H

S = 167 + 179

Total outcome (S) = 346

Finally, we shall determine the probability of tails. This can be obtained as follow:

Number of Tails (T) = 167

Total outcome (S) = 346

Probability of tail, P(T) =?

P(T) = T / S

P(T) = 167 / 346

P(T) = 0.483

Thus, the probability of tails is 167/346 or 0.483

3 0
3 years ago
Help................​
guapka [62]

Answer:

6.2 a QR

6.2 b 180

6.3 a By aas axiom

5 0
3 years ago
10. Use the data to determine the missing values in the five-number summary.
exis [7]

Answer:

Q1 - 2

Q1 - 5

Q3 - 7

maximum 9

minimum 1

Step-by-step explanation:

order the numbers from least to greatest

7 0
3 years ago
A circle has been split into 8 sectors each of which can be colored as 4 different colors, and no consecutive sectors are colore
Eva8 [605]

Answer:

5832 ways

Step-by-step explanation:

Since the circle has 8 sectors and there is 4 colour,

Assuming the sectors are numbered 1 to 8,

Sector 1 : can be coloured with any of the 4 colour in 4 ways

Sector 2 can be coloured with any of the remaining 3 colours in 3 ways

Sector 3 in 3 ways without using the colour in sector 2

Sector 4 in 3 ways without using the colour in sector 3

Sector 5 in 3 ways without using the colour in sector 4

Sector 6 in 3 ways without using the colour in sector 5

Sector 7 in 3 ways without using the colour in sector 6

Sector 8 in 2 ways without using the colours in sector 1 and 7

Number of ways of colouring = 4*3*3*3*3*3*3*2 = 5832 ways

3 0
3 years ago
El Club de Matemáticas está horneando pasteles para una venta de
SVETLANKA909090 [29]

Answer:

56

Step-by-step explanation:

El problema se puede transcribir en esta ecuación:

2x + x = 168

siendo x las nectarinas

sumas los términos de x:

3x=168

despejas x:

x = 168 ÷ 3

x = 56

5 0
2 years ago
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