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Ivan
3 years ago
6

What is the probability of rolling an even number when rolling a 6-sided die?

Mathematics
1 answer:
lukranit [14]3 years ago
7 0

Answer:

B.1/2

Step-by-step explanation:

Half of the numbers on a dice are even, so you have a 1 half probability of landing on an even number

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Among 43,592 in-hospital patients who had cardiac arrest during the day, 23,549 survived. Among 27,963 patients at night, 7,804
kumpel [21]

Using the z-distribution, it is found that since the p-value of the test is less than 0.01, there is enough evidence to conclude that survival rates are different for day and night.

<h3>What are the hypothesis tested?</h3>

At the null hypothesis, it is tested if the proportions are the same, that is, the subtraction of them is 0, hence:

H_0: p_D - p_N = 0

At the alternative hypothesis, it is tested if the proportions are different, that is:

H_1: p_D - p_N \neq 0

<h3>What are the mean and the standard error for the distribution of differences?</h3>

For each sample, they are given as follows:

  • p_D = \frac{23549}{43592} = 0.5402, s_D = \sqrt{\frac{0.5402(0.4598)}{43592}} = 0.0024
  • p_N = \frac{7804}{27963} = 0.2791, s_N = \sqrt{\frac{0.2791(0.6209)}{27963}} = 0.0025

Hence, for the distribution of differences, they are given by:

  • \overline{p} = p_D - p_N = 0.5402 - 0.2791 = 0.2611
  • s = \sqrt{s_D^2 + s_N^2} = \sqrt{0.0024^2 + 0.0025^2} = 0.0035.

<h3>What is the test statistic?</h3>

The test statistic is given by:

z = \frac{\overline{p} - p}{s}

In which p = 0 is the value tested at the null hypothesis.

Hence:

z = 0.2611/0.0035

z = 74.6.

<h3>What is the p-value of the test?</h3>

Using a z-distribution calculator, with z = 74.6, with a two-tailed test, as we are testing if the proportion is different of a value, the p-value is of 0.

Since the p-value of the test is less than 0.01, there is enough evidence to conclude that survival rates are different for day and night.

More can be learned about the z-distribution at brainly.com/question/13873630

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You should put this in Desmos, it’s online for graphing.
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Answer:

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A student takes ten exams during a semester and receives the following grades: 90, 85, 97, 76, 89, 58, 82, 102, 70, and 67. Find
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Formula: Minimum = first element of set First Quartile = (n+1)/4 Median = (n+1)/2 Third Quartile = 3(n+1)/4 Maximum = Last element of set. Solution:<span> The five number summary of ( 90, 85, 97, 76, 89, 58, 82, 102, 70, and 67) is, Minimum = 58 First Quartile = 70 Median: = 83.5 Third Quartile = 90 Maximum = 102</span>
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