Answer:
broad sense heritability = 0.75
Step-by-step explanation:
Step 1: Variables
phenotypic variation (Vp)
genotype variation (Vg)
environment variation (Ve)
broad sense heritability (H)
Step 2: Formulas:
H = Vg / Vp
Vp = Vg + Ve
Vg = Vp - Ve
Step 3: Given data
Vp = 20
Ve = 5
Step 4: Computation
Vg = 20 - 5 = 15
H = 15 / 20
H = 0.75
Hope this helps!
Answer:
Samuel's hourly rate after n seasons with the company is f(n)= 12.50 + 0.35*n. After 18 seasons with the company, Samuel's hourly rate will be 18.8 $ /hr.
Step-by-step explanation:
You know that Samuel's starting pay is $12.50/hr and for each season Samuel remains with the company, he receives a $0.35/hr raise.
Samuel's hourly rate after n seasons at the company will then be:
f(n)= 12.50 + 0.35*n
To determine the hourly rate after 18 seasons, you must replace the value n with 18:
f(18)= 12.50 + 0.35*18
Solving you get:
f(18)= 12.50 + 6.3
f(18)= 18.8
<u><em>Samuel's hourly rate after n seasons with the company is f(n)= 12.50 + 0.35*n. After 18 seasons with the company, Samuel's hourly rate will be 18.8 $ /hr. </em></u>
Answer:
Your question but don't know how to solve it like a dog
Answer:
10/3, or 3 1/3.
Step-by-step explanation:
3/1 + 1/3
3 + 1/3
9+1/3
10/3, or 3 1/3.