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KATRIN_1 [288]
4 years ago
8

If f(x)=4x^5+5x^4+1, then what is the remainder when f(x) is divided by x-2

Mathematics
1 answer:
monitta4 years ago
4 0

Answer:

Remainder 209

Step-by-step explanation:

f(x)= 4x⁵+5x⁴+1  

x-2=0⇒x=2

Putting x=2 in the above equation

f(x)= 4(2)⁵ +5(2)⁴+1

f(x)= 4(32) +5(16) +1

f(x)= 128 +80+1

f(x)= 209

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Find the midpoint of the line segment with end coordinates of:(−2,−4) and (2,−10)
zhuklara [117]

Answer:

Step-by-step explanation:

By using mid point formula ,

(X,Y) =( X1+X2/2) , Y1 +Y2/2

(-2+2/2) , (-4-10/2)

or, (0/2), (-7)

6 0
4 years ago
The diameter of a semicircle is 4 kilometers what is the semicircle's radius
sammy [17]

Answer:

To find the radius, just take half of the diameter. The answer is 2.

Step-by-step explanation:

Semicircle Area and Perimeter

Area (A)

6.2832in²

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Hope this helped!!!

5 0
3 years ago
4 + 2(5k+5) = 94 factoring
Scilla [17]
I hope this helps you 2.5. (k+1)=94-4 10. (k+1)=90 k+1=9 k=8
5 0
3 years ago
Read 2 more answers
7.90×10^−2/1.0×10^−5
Nitella [24]

Answer:

\frac{7.90 \times  {10}^{ - 2} }{1.0 \times  {10}^{ - 5} }  \\  = 7.9 \times  {10}^{5 - 2}  \\ = 7.9 \times  {10}^{3}

4 0
3 years ago
To find the weight of gold in a 22 karat gold object, multiply the objects weight by 0.917. To find the weight of a 18 karat gol
makkiz [27]

We are given:

The weight of gold in a 22 karat gold object = 0.917 times objects weight.

The weight of gold in a 18 karat gold object = 0.583 times objects weight.

We need to find the weight of gold in 73.5 ounces of statue for 22 karat and for 18 karat.

For 73.5 ounces of statue 22 karat gold = 0.917 × 73.5 = 67.3995 ounces gold.

For 73.5 ounces of statue 18 karat gold = 0.583 ×73.5 = 42.8505 ounces gold.

67.3995 -  42.8505 = 24.549 ounces of gold.

<h3>Therefore, 22 karat gold statue contains more gold and it contain 24.549 ounces more gold.</h3>
6 0
3 years ago
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