Given:
A bird was sitting 16 feet from the base of an oak tree and flew 20 feet to reach the top of the tree.
To find:
The length of the tree.
Solution:
A bird was sitting 16 feet from the base of an oak tree.
Vertical distance between bird and base = 16 feet
Then the bird flew 20 feet to reach the top of the tree.
Now, the vertical distance between bird and base = (16+20) feet
So, length of the oak tree is it the sum of 16 feet and 20 feet.
feet
feet
Therefore, the length of the oak tree is 36 feet.
Answer:
1-6 you need to write the JHI DEF where the radius center point is in the middle of each shape next to 1-6 some have 2 shapes so use 6 letters there.
Step-by-step explanation:
1. Area = 72 of 360 = 20% of 716.3 = 143.26inch*2 =JHI
2.Area = 19 of 360 = 68.4% of 69.4 = 47.46km^2 =DEF
3. Area = 92 of 360 = 25.56% of 153.9 = 39.33cm^2
4. Area = 226 of 360 = 64.57% of 706.9 = 456.45ft^2
5. Area = 74 of 360 = 20.55% of 153.9 =31.63 inch^2
6. Area = 326 of 360 = 90.56% of 1452 -137.07 = 1314.93m^2
Answer:
Each Pencil Cost 4 Dollars
Step-by-step explanation:
First you can subtract 21 by 9 to get 12 dollars which shows how much he spent.
Second you can divide 12 by 3 to get 4 dollars spent. So he spent 4 dollars on each pencil.
Answer:
g(x)
Step-by-step explanation:
The vertex of g(x) as shwon in the graph is located in the point wich coordinates are (3.5,6.25) approximatively
We need to khow the coordinates of f(x) vertex
- Here is a way without derivating:
f(x) = -x² + 4x -5
let a be the leading factor, b the factor of x and c the constant:
The coordinates of a vertex are: (
, f() )
-b/2a = -4/ (-1*2) = 4/2 = 2
f(2)= -2²+4*2-4 = -4+4-4 = -4
obviosly f(x) has a minimum wich less than g(x)'s maximum
Answer:
165 mL
Step-by-step explanation:
Density is mass divided by volume:
D = M / V
Solving for volume:
V = M / D
The density is given in g/mL. So first let's convert the mass from kg to g:
2.25 kg × (1000 g / kg) = 2250 g
Plugging in values:
V = (2250 g) / (13.6 g/mL)
V = 165.4 mL
Rounded to 3 significant figures, the volume is 165 mL.
