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3 years ago

11

Please answer correct it is revision for my sats

2 answers:

natita [175]3 years ago

5 0

4.00 totally: you divide 2.40 by 6 then multiply the number you get by 10

tresset_1 [31]3 years ago

5 0

Six chocolate eggs equal $2.40, thus each wouldbe 40c ($2.40/6). Coming to this conclusion, we can suggest that ten of these chocolate eggs would cost $4.00 (40c x 10 chocolate eggs).
I hope this helped.

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rick earns $8.50 per hour at his mother office. He plans on working 12.5 hours this week. How much money will rick earn?

marusya05 [52]

That would be 8.50 times 12.5 which is $106.25

7 0

3 years ago

Read 2 more answers

Simplify the square root of 27x^12/300x^8

Darina [25.2K]

The first thing we are going to do is rewrite the expression correctly.
We have:
root (27x ^ 12 / 300x ^ 8)
Rewriting:
root ((27/300) * (x ^ 12 / x ^ 8))
root ((9/100) * (x ^ (12-8)))
root ((9/100) * (x ^ (4)))
root ((9/100) * (x ^ (4)))
3 * x ^ 2 * root ((1/100)
(3 * x ^ 2) / 10
(3/10) * (x ^ 2)
Answer:
(3/10) * (x ^ 2)

6 0

3 years ago

Read 2 more answers

A pecan pie is being served for dessert. One piece of pie has an arc length of 7.85 in. It has been cut into 8 equal pieces. Wha

pishuonlain [190]

Answer: 10 inches.

Step-by-step explanation:

Since the pecan pie is a circle, you can use this formula:

$arc\ length=r\theta$

Where "r" is the radius and $\theta$ is the central angle of the arc in radians.

If the pecan pie has been cut into 8 equal pieces then the central angle is:

$\theta=\frac{2\pi}{8}\\\\\theta={\frac{\pi}{4}$

Now you know the arc length and the central angle, then, you can solve for "r" from $arc\ length=r\theta$ :

$\frac{arc\ length}{\theta} =r$

Substituting values, you get that the radius of the pecan pie rounded to the nearest whole number is:

$r=\frac{7.85in}{\frac{\pi}{4}}\\\\r=10in$

8 0

3 years ago

Suppose that the Celsius temperature at the point (x, y) in the xy-plane is T(x, y) = x sin 2y and that distance in the xy-plane

liraira [26]

Missing information:

How fast is the temperature experienced by the particle changing in degrees Celsius per meter at the point

$P = (\frac{1}{2}, \frac{\sqrt 3}{2})$

Answer:

$Rate = 0.935042^\circ /cm$

Step-by-step explanation:

Given

$P = (\frac{1}{2}, \frac{\sqrt 3}{2})$

$T(x,y) =x\sin2y$

$r = 1m$

$v = 2m/s$

Express the given point P as a unit tangent vector:

$P = (\frac{1}{2}, \frac{\sqrt 3}{2})$

$u = \frac{\sqrt 3}{2}i - \frac{1}{2}j$

Next, find the gradient of P and T using: $\triangle T = \nabla T * u$

Where

$\nabla T|_{(\frac{1}{2}, \frac{\sqrt 3}{2})} = (sin \sqrt 3)i + (cos \sqrt 3)j$

So: the gradient becomes:

$\triangle T = \nabla T * u$

$\triangle T = [(sin \sqrt 3)i + (cos \sqrt 3)j] * [\frac{\sqrt 3}{2}i - \frac{1}{2}j]$

By vector multiplication, we have:

$\triangle T = (sin \sqrt 3)* \frac{\sqrt 3}{2} - (cos \sqrt 3) \frac{1}{2}$

$\triangle T = 0.9870 * 0.8660 - (-0.1606 * 0.5)$

$\triangle T = 0.9870 * 0.8660 +0.1606 * 0.5$

$\triangle T = 0.935042$

Hence, the rate is:

$Rate = \triangle T = 0.935042^\circ /cm$

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2 years ago

Evaluate 2/3+3/4 <br> 1and5/12

chubhunter [2.5K]

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1 + 5/12 = 12/12 + 5/12 = 17/12 = 1 5/12

2/3 + 3/4 = 1 + 5/12

6 0

3 years ago