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Elan Coil [88]
3 years ago
10

Pls help me out i need the answer now!! Tysm

Mathematics
2 answers:
Nastasia [14]3 years ago
8 0

Answer:

There are 3435 no votes.

Step-by-step explanation:

The formula would be set up as ratios (or fractions). The ratio is 7:5, which in total is 12. There were 5 no answers out of 12, so the fraction = 5/12.

The second fraction has a total of 8244, however you do not know the amount of no votes, so the variable placeholder will be called "x".

The final formula would be:

 5/12 = x/8244

 You do cross multiplication and you get:

12x = 41220. You divide both sides, and you get x = 3435

nydimaria [60]3 years ago
3 0

Answer:

there were 3435 no voters

hope my answer help

Step-by-step explanation:

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victus00 [196]
Nine tenths = 0.9
Twenty hundredths is 0.2
Two hundredths is 0.02
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The number with the smallest value is 0.02, or two hundredths.

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A manufacturer of nails claims that only 4% of its nails are defective. A random sample of 20 nails is selected, and it is found
irakobra [83]

Answer:

The p-value of the test is 0.0853 > 0.05, which means that there is not enough evidence to reject the manufacturer's claim based on this observation.

Step-by-step explanation:

A manufacturer of nails claims that only 4% of its nails are defective.

At the null hypothesis, we test if the proportion is of 4%, that is:

H_0: p = 0.04

At the alternative hypothesis, we test if the proportion is more than 4%, that is:

H_a: p > 0.04

The test statistic is:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

In which X is the sample mean, \mu is the value tested at the null hypothesis, \sigma is the standard deviation and n is the size of the sample.

4% is tested at the null hypothesis

This means that \mu = 0.04, \sigma = \sqrt{0.04*0.96}

A random sample of 20 nails is selected, and it is found that two of them, 10%, are defective.

This means that n = 20, X = 0.1

Value of the test statistic:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

z = \frac{0.1 - 0.04}{\frac{\sqrt{0.04*0.96}}{\sqrt{20}}}

z = 1.37

P-value of the test and decision:

Considering an standard significance level of 0.05.

The p-value of the test is the probability of finding a sample proportion above 0.1, which is 1 subtracted by the p-value of z = 1.37.

Looking at the z-table, z = 1.37 has a p-value of 0.9147

1 - 0.9147 = 0.0853

The p-value of the test is 0.0853 > 0.05, which means that there is not enough evidence to reject the manufacturer's claim based on this observation.

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2 years ago
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