<h3>f(x)=3x³-13x²-3x+45</h3><h3>f(x)=3x³-9x²-4x²+12x-15x+45</h3><h3>f(x)=3x²(x-3)-4x(x-3)-15(x-3)</h3><h3>f(x)=(x-3)(3x²-4x-15)</h3><h3>f(x)=(x-3)(x-3)(3x+5)</h3><h2>f(x)=(x-3)²(3x+5)</h2>
<h3><u>Roots:</u></h3><h3>x=3</h3><h3>x=-5/3</h3>
Answer: The required derivative is 
Step-by-step explanation:
Since we have given that
![y=\ln[x(2x+3)^2]](https://tex.z-dn.net/?f=y%3D%5Cln%5Bx%282x%2B3%29%5E2%5D)
Differentiating log function w.r.t. x, we get that
![\dfrac{dy}{dx}=\dfrac{1}{[x(2x+3)^2]}\times [x'(2x+3)^2+(2x+3)^2'x]\\\\\dfrac{dy}{dx}=\dfrac{1}{[x(2x+3)^2]}\times [(2x+3)^2+2x(2x+3)]\\\\\dfrac{dy}{dx}=\dfrac{4x^2+9+12x+4x^2+6x}{x(2x+3)^2}\\\\\dfrac{dy}{dx}=\dfrac{8x^2+18x+9}{x(2x+3)^2}](https://tex.z-dn.net/?f=%5Cdfrac%7Bdy%7D%7Bdx%7D%3D%5Cdfrac%7B1%7D%7B%5Bx%282x%2B3%29%5E2%5D%7D%5Ctimes%20%5Bx%27%282x%2B3%29%5E2%2B%282x%2B3%29%5E2%27x%5D%5C%5C%5C%5C%5Cdfrac%7Bdy%7D%7Bdx%7D%3D%5Cdfrac%7B1%7D%7B%5Bx%282x%2B3%29%5E2%5D%7D%5Ctimes%20%5B%282x%2B3%29%5E2%2B2x%282x%2B3%29%5D%5C%5C%5C%5C%5Cdfrac%7Bdy%7D%7Bdx%7D%3D%5Cdfrac%7B4x%5E2%2B9%2B12x%2B4x%5E2%2B6x%7D%7Bx%282x%2B3%29%5E2%7D%5C%5C%5C%5C%5Cdfrac%7Bdy%7D%7Bdx%7D%3D%5Cdfrac%7B8x%5E2%2B18x%2B9%7D%7Bx%282x%2B3%29%5E2%7D)
Hence, the required derivative is
Slope-intercept form looks like this: y = mx + b. For your equation, simply add 3x on both sides: y = 3x + 19.
Answer:
the first and last one
Step-by-step explanation:
An angle bisector is a line or ray that divides an angle into two congruent angles
so
in this problem
m∠RST=m∠RSV+m∠VST
m∠RSV=m∠VST
hence
m∠RST=2*m∠RSV --------> equation 1
we have
m∠RST=(6x-24)
m∠RSV=(2x+8)
Substitute in the equation 1
6x-24=2*(2x+8)
6x-24=4x+16
6x-4x=16+24
2x=40
x=40/2
x=20 degrees
therefore
the value of x is 20 degrees
Tell me if I’m wrong
