Answer:
x∈[2nπ−5π/6, 2nπ−π/6]∪{(4n+1)π/2}, n ϵ I
Step-by-step explanation:
1−2sin2 x≤−sin x ⇒ (2sin x+1)(sin x−1)≥0
sin x≤−1/2 or sin x≥1
−5π/6+2nπ≤x≤−π/6+2nπ or , n ϵ I x=(4n+1)π/2, n ϵ I⇒ -5π6+2nπ≤x≤-π6+2nπ or , n ϵ I x=4n+1π2, n ϵ I (as sin x = 1 is valid only)
In general⇒ In general x∈[2nπ−5π/6, 2nπ−π/6]∪{(4n+1)π/2}, n ϵ I
Given:
The table and the relative frequency histogram show the distribution of the number of tails and three coins are tossed.
To find:
The probability 
.
Solution:
In the given table T represents the number of tails.
From the given table it is clear that the value of probability is 
and 
. So,
Therefore, the probability is equal to .
Recall that the sum of all 3 angles of a triangle is 180. So,
82 + 45 + x = 180>> 127 + x = 180
>> x = 180 - 127
>> x = 53 (final answer)
Sec Ф=1/cos Ф=cos⁻¹Ф
correct answers: a. sec Ф=cos⁻¹Ф and d. sec Ф=1/ cos Ф
