262.5 miles
explanation 1/4 is half of 1/2 so 52.5 is half of 105 and then 210 for an hour of travel
Answer:
2x(5x+1)(2x+3)=0
Step-by-step explanation:
x{20x^2+34x+6}=0
2x(10x^2+17+3)=0
2x(10x^2+15x+2x+3)=0
2x{5x(2x+3)+1(2x+3)}=0
2x(5x+1)(2x+3)=0
R=S*0.5^(t/8)
<span>R is the remaining amount </span>
<span>S is the starting amount (500) </span>
<span>0.5^ is for the HALF in half-life </span>
<span>t/8 show that every 8 ts (every 8 hours), it will be halved once </span>
<span>...so plug in 500mg for the general solution... </span>
<span>R=(500)*(0.5)^(t/8) </span>
<span>... plug in 24h to solve for after 24h </span>
<span>R=(500)*(0.5)^(24/8) </span>
<span>R=(500)*(0.5)^(3) </span>
<span>R=(500)*(0.125) </span>
<span>R=(0.0625) </span>
<span>...therefore there with be 0.0625 mg of the dose remaining</span>
Answer:
C
Step-by-step explanation:
Lucia's claim is correct since any rotation that is a multiple of 45° carries a square onto itself
Answer:
Step-by-step explanation:
First we have to write down what it says in the question in as an expression. So we know that there is already 3 people on Britany's team (herself and the two friends), that in order to participate in the league you will need at least 9 players, and that the team can have a maximum of 15 player. So....
Let "x" be the number of people who decided to join Britany and her friends
Let "y" be the total number of people on Britanie's team, then .....
3 + x = y
Now we need to remember that in order to participate in the league you will need at least 9 players, and that the team can have a maximum of 15 player. We can write that down as......
Now from this we know that the minimum value that x would need to take in order for Brittany's team to participate can be found by solving 3 + x = 9. The maximum value that x would need to take in order for Brittany's team to participate can be found by solving 3 + x = 15. And so we get.....
Minimum value:
3 + x = 9
x = 9 -3
x = 6
Maximum value:
3 + x = 15
x = 15 - 3
x = 12
Now we know that x will be equal to any integer between 6 and 12 so