All categories

3 years ago

What is X in this equation? 3x+55=9x-5Please Explain.

Mathematics

2 answers:

Inessa [10]3 years ago

5 0

Answer:

x=10

Step-by-step explanation:

$\mathrm{Subtract\:}55\mathrm{\:from\:both\:sides}\\3x+55-55=9x-5-55$

$\mathrm{Simplify}\\3x=9x-60$

$\mathrm{Subtract\:}9x\mathrm{\:from\:both\:sides}\\3x-9x=9x-60-9x$

$\mathrm{Simplify\:}again\\-6x=-60$

$\mathrm{Divide\:both\:sides\:by\:}-6\\\frac{-6x}{-6}=\frac{-60}{-6}$

$\mathrm{\:Simplify\:one\:more\:time}\\x=10$

I hope this helps you out!

Have a wonderful afternoon!

klasskru [66]3 years ago

3 0

Answer:

x = 10

Step-by-step explanation:

3x + 55 = 9x - 5 (add 5 to both sides)

3x + 55 + 5 = 9x - 5 + 5

3x + 60 = 9x (subtract 3x from both sides)

60 = 9x - 3x

60 = 6x (rearrange)

6x = 60 (divide both sides by 6)

x = 60/6

x = 10

You might be interested in

the lions won 16 games last year. this year the lions won 20 games. what is the percent increase in number of games the lions wo

jarptica [38.1K]

Last year won the lions 16 games last year and into this year the Lions won 20 games.

as the percentage increase is:

20/16

(20/4) / (16/4)

5/4
<span>
1.25 (125%)</span>

6 0

4 years ago

Find the limit

Lana71 [14]

Step-by-step explanation:

<h3>Appropriate Question :-</h3>

Find the limit

$\rm \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{x-2}{x^2-x}-\dfrac{1}{x^3-3x^2+2x}\right]$

$\large\underline{\sf{Solution-}}$

Given expression is

$\rm \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{x-2}{x^2-x}-\dfrac{1}{x^3-3x^2+2x}\right]$

On substituting directly x = 1, we get,

$\rm \: = \: \sf \dfrac{1-2}{1 - 1}-\dfrac{1}{1 - 3 + 2}$

$\rm \: = \sf \: \: - \infty \: - \: \infty$

which is indeterminant form.

Consider again,

$\rm \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{x-2}{x^2-x}-\dfrac{1}{x^3-3x^2+2x}\right]$

can be rewritten as

$\rm \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{x-2}{x(x - 1)}-\dfrac{1}{x( {x}^{2} - 3x + 2)}\right]$

$\rm \: = \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{x-2}{x(x - 1)}-\dfrac{1}{x( {x}^{2} - 2x - x + 2)}\right]$

$\rm \: = \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{x-2}{x(x - 1)}-\dfrac{1}{x( x(x - 2) - 1(x - 2))}\right]$

$\rm \: = \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{x-2}{x(x - 1)}-\dfrac{1}{x(x - 2) \: (x - 1))}\right]$

$\rm \: = \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{ {(x - 2)}^{2} - 1}{x(x - 2) \: (x - 1))}\right]$

$\rm \: = \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{ (x - 2 - 1)(x - 2 + 1)}{x(x - 2) \: (x - 1))}\right]$

$\rm \: = \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{ (x - 3)(x - 1)}{x(x - 2) \: (x - 1))}\right]$

$\rm \: = \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{ (x - 3)}{x(x - 2)}\right]$

$\rm \: = \: \sf \: \dfrac{1 - 3}{1 \times (1 - 2)}$

$\rm \: = \: \sf \: \dfrac{ - 2}{ - 1}$

$\rm \: = \: \sf \boxed{2}$

Hence,

$\rm\implies \:\boxed{ \rm{ \:\rm \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{x-2}{x^2-x}-\dfrac{1}{x^3-3x^2+2x}\right] = 2 \: }}$

$\rule{190pt}{2pt}$

7 0

3 years ago

Read 2 more answers

What is the voume of depth 1 2/3 inches and length of 2 1/3 inches and width 2 inches

Vlad [161]

Answer:

20/9 or 2 2/9 or 2.2 repeating

Step-by-step explanation:

7 0

3 years ago

A table top is 1 3/4 feet wide and 3 1/2 feet long . what is the area of the rectangular table top?

Sergeu [11.5K]

Answer:

6.125 or 49/8

Step-by-step explanation:

1 3/4 times 3 2/4

7 0

3 years ago

Emily and Zach read a total of 32 books in four months. Emily read 12 books. Which equations

DerKrebs [107]

Answer:

Step-by-step explanation:

you take away 12 from the total and you'll find how many Zach read (20) then 12+20=32

4 0

3 years ago

Read 2 more answers

What is X in this equation? 3x+55=9x-5Please Explain.​

What is X in this equation? 3x+55=9x-5Please Explain.