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3 years ago

What is X in this equation? 3x+55=9x-5Please Explain.

Mathematics

2 answers:

Inessa [10]3 years ago

5 0

Answer:

x=10

Step-by-step explanation:

$\mathrm{Subtract\:}55\mathrm{\:from\:both\:sides}\\3x+55-55=9x-5-55$

$\mathrm{Simplify}\\3x=9x-60$

$\mathrm{Subtract\:}9x\mathrm{\:from\:both\:sides}\\3x-9x=9x-60-9x$

$\mathrm{Simplify\:}again\\-6x=-60$

$\mathrm{Divide\:both\:sides\:by\:}-6\\\frac{-6x}{-6}=\frac{-60}{-6}$

$\mathrm{\:Simplify\:one\:more\:time}\\x=10$

I hope this helps you out!

Have a wonderful afternoon!

klasskru [66]3 years ago

3 0

Answer:

x = 10

Step-by-step explanation:

3x + 55 = 9x - 5 (add 5 to both sides)

3x + 55 + 5 = 9x - 5 + 5

3x + 60 = 9x (subtract 3x from both sides)

60 = 9x - 3x

60 = 6x (rearrange)

6x = 60 (divide both sides by 6)

x = 60/6

x = 10

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Step-by-step explanation:

a) No. of cells in 1 cm³

$\text{No. of cells} =\text{1 cm}^{3} \times\left( \dfrac{\text{1 m}}{\text{100 cm}}\right )^{3} \times \left (\dfrac{1 \, \mu \text{m} }{10^{-6}\,\text{ m}}\right )^{3} \times \dfrac{\text{1 cell}}{\text{50 $\,\mu$m}^{3}} = \mathbf{2.00 \times 10^{10}} \textbf{ cells}$

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$\text{No. of cells} = \text{1 L} \times \dfrac{\text{1000 cm}^{3}}{\text{1 L}} \times \dfrac{2 \times 10^{10} \text{ cells}}{\text{1 cm}^{3}} = \mathbf{2.00 \times 10^{13}} \textbf{ cells}$