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egoroff_w [7]
3 years ago
14

Yoshi is painting a large wall in the park. He measures the wall and finds that the dimensions are 4 m by 20 m. Yoshi has a can

of paint that will cover an area of 81 m^2. Should he buy more paint? Explain.
Mathematics
1 answer:
-BARSIC- [3]3 years ago
8 0

No. The area of a square/rectangle is length * height, and 4 * 20 is 80m^2. Because Yoshi has a can of paint that can cover 81m^2, and 81m^2 > 80m^2, Yoshi does NOT need to buy more paint.

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Joes age (j) is half Martha’s (m). Combined, their age is 42. What are their ages?
svp [43]

Answer:

Joe is 14.

Martha is 28.

Step-by-step explanation:

Use the variables and information from the question to make equations.

If Joe's age is half Martha's:

(1/2)m = j     OR     2j = m

If their ages combined is 42:

m + j = 42

We can substitute the equation m=2j into equation m + j = 42, replacing "m".

m + j = 42    Substitute m for 2j

2j + j = 42     Combine like terms, terms with same varables

3j = 42     Divide both sides by 3 to isolate j

j = 14       Joe's age

Since j = 14, we can substitute it into equation m=2j to find "m".

m = 2j       Substitute j for 14

m = 2(14)     Simplify

m = 28       Martha's age

Therefore Joe is 14 and Martha is 28.

5 0
3 years ago
URGENTTT Whos correct and Why?
andreyandreev [35.5K]
Bills right because the y-intercept is 50 so I’m think what he’s saying about the rocket being launched 50 feet above water is right
4 0
3 years ago
What is the midpoint of (8,10) and (-8,8)
nasty-shy [4]

9514 1404 393

Answer:

  (0, 9)

Step-by-step explanation:

The midpoint coordinates are the averages of the end point coordinates.

  M = (A +B)/2

  M = ((8, 10) +(-8, 8))/2 = (8 -8, 10+8)/2 = (0, 18)/2

  M = (0, 9)

The midpoint is (0, 9).

4 0
3 years ago
A page should have perimeter of 42 inches. The printing area within the page
Tamiku [17]

Overall  dimensions of the page in order to maximize the printing area is  page should be 11 inches wide and 10 inches long .

<u>Step-by-step explanation:</u>

We have , A page should have perimeter of 42 inches. The printing area within the page  would be determined by top and bottom margins of 1 inch from each side, and the  left and right margins of 1.5 inches from each side. let's assume  width of the page be x inches  and its length be y inches So,

Perimeter = 42 inches

⇒ 2(x+y) = 42\\x+y = 21\\y = 21-x

width of printed area = x-3  & length of printed area = y-2:

area = length(width)

area = (x-3)(y-2)\\area = (x-3)(21-x-2)\\area = (x-3)(19-x)\\area = -x^{2} + 22x -57

Let's find \frac{d(area)}{dx}:

\frac{d(area)}{dx} = \frac{d(-x^{2}+22x-57)}{dx} = -2x +22 , for area to be maximum \frac{d(area)}{dx}= 0

⇒ -2x+22 = 0\\2x =22\\x=11 inches

And ,

y = 21-x\\y = 21-11\\y = 10 inches

∴ Overall  dimensions of the page in order to maximize the printing area is  page should be 11 inches wide and 10 inches long .

7 0
3 years ago
Umm I don’t remember this please help. I will give correct answer brainliest
VikaD [51]

Answer:

Option D

Step-by-step explanation:

F=\frac{9}{5}C+32\\\\F-32=\frac{9}{5}C  \\\\5(F-32)=9C\\\\\frac{5(F-32)}{9}=C  \\\\C=\frac{5}{9}( {F-32})

For F=77°F

C=\frac{5}{9}(F-32) \\\\C=\frac{5}{9}(77-32)\\\\C=\frac{5}{9}(45)\\\\C=\frac{225}{9} \\\\C=25

7 0
3 years ago
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