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egoroff_w [7]
3 years ago
14

Yoshi is painting a large wall in the park. He measures the wall and finds that the dimensions are 4 m by 20 m. Yoshi has a can

of paint that will cover an area of 81 m^2. Should he buy more paint? Explain.
Mathematics
1 answer:
-BARSIC- [3]3 years ago
8 0

No. The area of a square/rectangle is length * height, and 4 * 20 is 80m^2. Because Yoshi has a can of paint that can cover 81m^2, and 81m^2 > 80m^2, Yoshi does NOT need to buy more paint.

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asambeis [7]

From the given information, a exists jointly proportional to b and c.

then $$a \propto b c$

Therefore, the value of a exists 2.

<h3>What is the value of a?</h3>

Given, a exists jointly proportional to b and c.

$$a \propto b c$

Taking K as the constant of proportionality.

a = K b c

For b = 8 and c = 9, the value of a = 4

4 = K(8)(9)

4 = 72 K

Dividing the equation by 72, we get

$K=\frac{1}{18}

Using the value of K in the equation:

$a=\frac{b c}{18}

Substitute the values of b = 2 and c = 18, in the above equation

$a=\frac{2 \times 18}{18} \\

a = 2

Therefore, the value of a exists 2.

To learn more the value of x refers to:

brainly.com/question/11874663

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6 0
9 months ago
How do you do 4x - 9 = 6x - 13? what do you subtract from both sides?
ohaa [14]
To start, you need to subtract 4x from both sides, that way, x is one one sid of the equation.

8 0
3 years ago
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Find the mean of the number set.<br>93, 81, 94, 78, 89, 92, 94, 99<br>Your answer divided by 7​
dimaraw [331]

Answer:

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Step-by-step explanation:

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8 0
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Semmy [17]

Answer:

see attachment for graph

Step-by-step explanation:

< or > : dashed line

≤ or ≥ : solid line

< or ≤ : shade below the line

> or ≥ : shade above the line

<u>To graph the line y < 3x-2</u>

Rewrite the equation as: y = 3x - 2

Find two points on the line:

when x = 0,  y = 3(0) - 2 = -2  →  (0, -2)

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Plots the found points (0, -2) and (3, 7).

Draw a straight, dashed line through the points.

<u>To graph the line y ≥ -x + 3</u>

Rewrite the equation as: y = -x + 3

Find two points on the line:

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Plots the found points (0, 3) and (3, 0).

Draw a straight, solid line through the points.

Shade above the solid line and below the dashed line to the right of where the two lines intersect.  <u>The shaded area is the area of all possible solutions</u>.

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