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saveliy_v [14]
2 years ago
7

The aquarium charges an entrance fee of $5 per child and $12 per adult. On one day, 100 people visited the aquarium. They collec

ted $780 in admission fees. Which system of equations could be used to determine the number of adults that visited the aquarium? Let c represent the number of children and a represent the number of adults.
Mathematics
1 answer:
igor_vitrenko [27]2 years ago
6 0

Answer:

We set up 2 equations

A) C + A = 100

B) 5C + 12A = 780

We multiply A by -5

A) -5C -5A = -500   then we add B

B) 5C + 12A = 780

7A = 280

Number of Adults = 40

5C = 780 - 40*12

5C = 780 -480

5C = 300

Number of Children = 60

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

Given

Nickels = x

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Required

Solve graphically

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0.05x\ +\ 0.01y\ \le0.80 because the worth of coins is not more than 0.80

So, we have the following equations:

x\ +\ y\ge 20

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Make y the subject in both cases:

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Divide through by 0.01

\frac{0.01y}{0.01} \le \frac{0.80}{0.01} -\frac{ 0.05x}{0.01}

y \le \frac{0.80}{0.01} -\frac{ 0.05x}{0.01}

y \le 80 -5x

The resulting inequalities are:

y \ge 20 - x

y \le 80 -5x

The two inequalities are plotted on the graph as shown in the attachment.

y \ge 20 - x --- Blue

y \ge 80 -5x --- Green

Point A on the attachment are possible solutions

At A:

(x,y) = (15,5)

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Answer:

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