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If a research team increases the sample size for a study, the power of their statistical tests will:

Viktor [21]

Answer: c) increase

Step-by-step explanation:

A sample is a finite subset of the entire population on which research statistical test regarding his/ her objective .

As the sample size increases it comes closer to the population size, and so converge to a better result of researcher's analysis.

It means the size of the sample is proportional to the power of their statistical tests.

∴ As the size of the sample increases the power of statistical test increases.

Hence, If a research team increases the sample size for a study, the power of their statistical tests will <u>increases</u>.

Therefore , the correct answer is : c) increase

3 0

3 years ago

a water tank holds 24,000 gallons. how many hours will it take for 2/3 of the water to be used if the water is used at an averag

Likurg_2 [28]

In the question, it is already mentioned that the water tank holds = 24,000 gallons
In the given question it is also mentioned that the need is to find the time required to use 2/3 of the total water that the tank holds.
So the need is to find the amount of water that equals 2/3 of the total water in the tank.
Then
Quantity of water that needed to be used = [24000 * (2/3)] gallons
= 16000 gallons
In the problem it is also mentioned that the average rate of consumption per day is 650 gallons.
So
650 gallons of water used in = 24 hours
16000 gallons of water will be used in = [(24/650) *16000] hours
= 590.77 hours
So the time required to consume 2/3 of the total water in the tank is 590.77 hours.

8 0

4 years ago

Find the 90% confidence interval for the population standard deviation given the following.

lions [1.4K]

Answer:

b. 2.01 < σ < 2.81

Step-by-step explanation:

The 90% confidence interval for the population standard deviation is calculated as:

$\sqrt{\frac{(n-1)*s^{2} }{X^2_{\alpha/2 } } }$ < σ < $\sqrt{\frac{(n-1)*s^{2} }{X^2_{1-\alpha/2 } } }$

Where n is equal to 51, s is equal to 2.34, $\alpha$ is 10%, $X^{2} _{\alpha /2}$ is the value for the Chi squared distribution with n-1 degrees of freedom that has a probability of $\alpha /2$ in the right tail and $X^{2} _{1-\alpha /2}$ is the value for the Chi squared distribution with n-1 degrees of freedom that has a probability of $1-\alpha /2$ in the right tail.

So, replacing n by 51, s by 2.34, $X^{2} _{\alpha /2}$ by 67.50 and $X^{2} _{1-\alpha /2}$ by 34.76, we get that the The 90% confidence interval is equal to:

$\sqrt{\frac{(51-1)*2.34^{2} }{67.50} } }$ < σ < $\sqrt{\frac{(51-1)*2.34^{2} }{34.76} } }$

2.01 < σ < 2.81

5 0

3 years ago

2 cans of paint hold 64 and 125 oz. if the cans are similar cylinders and the smaller lid has an area of 18 find the area of the

kramer

Answer:

The area of the bigger lid is approximately 29.2 square inches

Step-by-step explanation:

The given data are;

The volume held by one of the cans of paint, V₁ = 64 oz

The volume held by the other cans of paint, V₂ = 125 oz

The area of the smaller lid = 18 in²

Therefore,

The 64 Oz = The smaller can of paint

The 125 oz = The larger can of paint

The diameter of the smaller lid, d₁ = √(18 × 4/π) ≈ 4.787

The ratio of can volumes = (The ratio of can diameters)³

V₁/V₂ = (d₁/d₂)³

V₁/V₂ = 64/125

d₁/d₂ ≈ 4.787/d₂

64/125 = (4.787/d₂)³

4.787/d₂ = ∛(64/125) = 4/5

d₂ ≈ 4.878×5/4 = 6.0975

The area of the bigger lid, A₂ = π·d₂²/4

∴ A₂ = π × 6.0975²/4 ≈ 29.2

The area of the bigger lid, A₂ ≈ 29.2 in.²

6 0

3 years ago

ANSWER PLZ QUICK AND FAST WHAT

Pavlova-9 [17]

The answer to this question is C.

6 0

3 years ago