Area of square is numerically less than twice its diagonal by 2. Find its Perimeter.

1 answer:

8 0

2D-a^2=2

2(a√2) -a^2=2

a^2-2√2*a+2=0

2a= 2√2 + √(8-4*2) = 2√2
hence, perimeter = 4a = 2*2a=2*2√2 = 4√2

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