Move all terms that don't contain <span>xx</span> to the right side and solve.<span>
Which gets you, x=<span><span>10/7</span></span></span>
Answer:
C(n) = 4 n for all possible integers n in N. This statement is true when n=1 and proving that the statement is true for n=k when given that statement is true for n= k-1
Step-by-step explanation:
Lets P (n) be the statement
C (n) = 4 n
if n =1
(x+4)n = (x+4)(1)=x+4
As we note that constant term is 4 C(n) = 4
4 n= 4 (1) =4
P(1) is true as C(n) = 4 n
when n=1
Let P (k-1)
C(k-1)=4(k-1)
we need to proof that p(k) is true
C(k) = C(k-1) +1)
=C(k-1)+C(1) x+4)n is linear
=4(k-1)+ C(1) P(k-1) is true
=4 k-4 +4 f(1)=4
=4 k
So p(k) is true
By the principle of mathematical induction, p(n) is true for all positive integers n
Answer:
30°
Step-by-step explanation:
To make sure it's complete
477
The value of the first 7 from the left is 70.
If you divide 70 by 10, you get the value of the second seven, 7.
Another way to know this is equivalent fractions:
1/10 = 7/10
10 X 7 = 70
1 X 7 = 7
