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devlian [24]
3 years ago
10

Help! This is due today and I'm stuck on the last problem.

Mathematics
1 answer:
FrozenT [24]3 years ago
6 0

Answer:

Step-by-step explanation:

Square

519450.2

Holes

Semi-circle: 1/2*pi*r^2

diameter = 700/2 = 350 =radius

1/2*pi*350 = 175*pi

Triangle

1/2 b*h

1/2 200*400

100*400

40000

Take out the semi circle and triangle

560000-40000-175*pi

520000-175*pi = 519450.2

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What is not a description of slope?
nekit [7.7K]

Answer:

the ratio of horizontal change compared to vertical change

Step-by-step explanations

slope = difference of y/ difference of x

rise (y)  over (/)  run (x)

change in y over change in x  (y/x)

horizontal change (x): to vertical change (y) WRONG

3 0
3 years ago
Please help and explain
pogonyaev

Answer:

x = 12

Step-by-step explanation:

3x - 1 + x + 7 = 54

4x + 6 = 54

4x + 6 - 6 = 54 - 6

4x = 48

\frac{4x}{4}  =  \frac{48}{4}

x = 12

3(12) - 1 + (12) + 7 = 54

36 - 1 + 12 + 7 = 54

35 + 12 + 7 = 54

35 + 19 = 54

54 = 54

3 0
3 years ago
Read 2 more answers
Y=2/3x+10 what is the x-intercept?
REY [17]

Answer:

Step-by-step explanation:

The x intercept is 3 because it’s by the x

7 0
3 years ago
A Arrange the following integers in ascending order<br>1) 37, 41, 76, -2.25 -25<br>Answer: ​
madreJ [45]

ASCENDING ORDER

76,41,36,25,-2,-25

7 0
3 years ago
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The amount of time that a customer spends waiting at an airport check-in counter is a random variable with mean 8.2 minutes and
Ksju [112]

Answer:

A) 1

B) 1

C) 0

Step-by-step explanation:

The amount of time that a customer spends waiting at an airport check-in counter is a random variable with mean 8.2 minutes and standard deviation 1.5 minutes. Suppose that a random sample of n = 49 customers is observed. Find the probability that the average time waiting in line for these customers is A) Less than 10 minutes B) Between 5 and 10 minutes C) Less than 6 minutes

We solve this question using the z score formula

z = (x-μ)/σ/√n, where

x is the raw score

μ is the population mean

σ is the population standard deviation.

n = number of random samples

A) Less than 10 minutes

x < 10

z = 10 - 8.2/ 1.5 / √49

z = 8.4

P-value from Z-Table:

P(x<10) = 1

B) Between 5 and 10 minutes

For x = 5 minutes

z = 5 - 8.2/ 1.5 / √49

z = -14.93333

P-value from Z-Table:

P(x = 5) = 0

For x = 10 minutes

z = 10 - 8.2/ 1.5 / √49

z = 8.4

P-value from Z-Table:

P(x = 10) = 1

The probability that the average time waiting in line for these customers is between 5 and 10 minutes

P(x = 10) - P(x = 5)

= 1 - 0

= 1

C) Less than 6 minutes

x < 6

z = 6 - 8.2/ 1.5 / √49

z = -10.26667

P-value from Z-Table:

P(x<6) = 0

6 0
3 years ago
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