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solniwko [45]
3 years ago
9

Hey everyone! I’m back! Hope you enjoyed your weekend!

Mathematics
2 answers:
aalyn [17]3 years ago
5 0

Answer:

8 / 9 x 4 / 3

Step-by-step explanation:

8 / 9 divided by 3 / 4

= ( 8 / 9 ) / ( 3 / 4 )

= 8 / 9 x 4 / 3

baherus [9]3 years ago
5 0

Answer: 8/9 x 4/3

Step-by-step explanation:

One way to do this is, KCR. The K stand for keep, so you don't change the 8/9. the C stands for change. So, we change the division to multiplication. Lastly, the R stands for Reciprocal which means to swap the 3/4 and make is 4/3. So, we get 8/9 x4/3. Hope this helps!

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3 years ago
The driver of a 810.0 kg car decides to double the speed from 23.6 m/s to 47.2 m/s. What effect would this have on the amount of
Setler [38]

Answer:

  • KEi = 2.256×10^5 J
  • KEf = 9.023×10^5 J
  • 4 times as much work

Step-by-step explanation:

The kinetic energy for a given mass and velocity is ...

  KE = (1/2)mv^2 . . . . . m is mass

At its initial speed, the kinetic energy of the car is ...

  KEi = (1/2)(810 kg)(23.6 m/s)^2 ≈ 2.256×10^5 J . . . . . m is meters

At its final speed, the kinetic energy of the car is ...

  KEf = (1/2)(810 kg)(47.2 m/s)^2 ≈ 9.023×10^5 J

The ratio of final to initial kinetic energy is ...

  (9.023×10^5)/(2.256×10^5) = 4

4 times as much work must be done to stop the car.

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You know this without computing the kinetic energy. KE is proportional to the square of speed, so when the speed doubles, the KE is multiplied by 2^2 = 4.

8 0
3 years ago
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