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PSYCHO15rus [73]
3 years ago
13

7x-6-5x-7-2x simplify the expression

Mathematics
1 answer:
Lina20 [59]3 years ago
6 0
-13 is the simplified expression
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X=2 y=5<br> 2x^0y^-2<br> Please help
grandymaker [24]

Answer:

2/25

Step-by-step explanation:

7 0
3 years ago
just as a piece of wood that is 8 foot long he needs to cut pieces that are seven eighths of a foot long how many pieces will he
BlackZzzverrR [31]
He would make 7 peices
7 0
4 years ago
The value of a school bus reduces from $512000 to $343000in 3 years. Find the
Eva8 [605]

Answer:

<em>The uniform rate of depreciation is $56,333 per year, or 11% per year.</em>

Step-by-step explanation:

<u>Rate of Depreciation</u>

If some object has a certain value P and after some time t its value decreases to Q, the rate of depreciation is a measure of how much its value changed per unit time.

It can be calculated as:

\displaystyle R=\frac{P-Q}{t}

It can also be expressed as a percentage, dividing the previous value by P.

The school bus reduces its value from $512,000 to $343,000 in 3 years, thus:

\displaystyle R=\frac{512,000-343,000}{3}

\displaystyle R=\frac{169,000}{3}

R = 56,333 $/year

Expressed as a percentage:

R = 56,333 / 512,000 = 0.11

R = 11%/year

The uniform rate of depreciation is $56,333 per year, or 11% per year.

8 0
3 years ago
Una torre de 28.2 m de altura esta situada a la orilla de un rio, desde lo alto del edificio el ángulo de depresión a la orilla
Svet_ta [14]

Answer:

El ancho del río es 59.9 metros.

Step-by-step explanation:

El ancho del río lo podemos calcular con la siguiente relación trigonométrica asumiendo que la torre forma un triángulo rectángulo con el río:

tan(\theta) = \frac{CO}{CA}

En donde:

CA: es el cateto adyacente = Altura de la torre = 28.2 m

CO: es el cateto opuesto = ancho del río =?

θ: es el ángulo adyacente a CA

Dado que el ángulo de depresión (25.2°) está ubicado fuera de la parte superior de la hipotenusa del triángulo que forma la torre con la orilla opuesta del río, debemos calcular el ángulo interno (θ) como sigue:

\theta = (90 - 25.2)^{\circ} = 64.8 ^{\circ}

Ahora, el ancho del río es:

CO = tan(\alpha)*CA = tan(64.8)*28.2 = 59.9 m

Por lo tanto, el ancho del río es 59.9 metros.

Espero que te sea de utilidad!                  

4 0
3 years ago
Find the slope of the line graphed below.
Law Incorporation [45]

Answer:

8/5

Step-by-step explanation:

7 0
3 years ago
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