All categories

3 years ago

What are the roots of the quadratic function? f(x) = (x – 8)(x – 4)

Mathematics

1 answer:

artcher [175]3 years ago

8 0

Answer:

x = 8

x = 4

Step-by-step explanation:

You might be interested in

What is GCF and LCM of -5 and 56? Please Help! Will give Brainliest!

Nookie1986 [14]

Answer:

The GCF is 1 and the LCM 280

Step-by-step explanation:

I did this on a test and got it right

4 0

3 years ago

Read 2 more answers

Algebra 1 - which equation represents exponential growth?

Nataly_w [17]

Answer:

d. y =5(1.06)^x

Step-by-step explanation:

growth formula is

y = (1+r)^t

1+r has to be greater than 1

mustangps

7 0

2 years ago

Most major airlines allow passengers to carry two pieces of luggage (of a certain maximum size) onto the plane. However, their s

leonid [27]

Answer:

d) (179.20, 212.716)

Step-by-step explanation:

1000 : 345

569 : 195.96

Midpoint of (179.20, 212.716) is 195.958 which is the closest to 195.96

4 0

3 years ago

Show work please<br> \sqrt(x+12)-\sqrt(2x+1)=1

Nesterboy [21]

Answer:

$x=4$

Step-by-step explanation:

Given $\displaystyle\\\sqrt{x+12}-\sqrt{2x+1}=1$ , start by squaring both sides to work towards isolating $x$ :

$\displaystyle\\\left(\sqrt{x+12}-\sqrt{2x+1}\right)^2=\left(1\right)^2$

Recall $(a-b)^2=a^2-2ab+b^2$ and $\sqrt{a}\cdot \sqrt{b}=\sqrt{a\cdot b}$ :

$\displaystyle\\\left(\sqrt{x+12}-\sqrt{2x+1}\right)^2=\left(1\right)^2\\\implies x+12-2\sqrt{(x+12)(2x+1)}+2x+1=1$

Isolate the radical:

$\displaystyle\\x+12-2\sqrt{(x+12)(2x+1)}+2x+1=1\\\implies -2\sqrt{(x+12)(2x+1)}=-3x-12\\\implies \sqrt{(x+12)(2x+1)}=\frac{-3x-12}{-2}$

Square both sides:

$\displaystyle\\(x+12)(2x+1)=\left(\frac{-3x-12}{-2}\right)^2$

Expand using FOIL and $(a+b)^2=a^2+2ab+b^2$ :

$\displaystyle\\2x^2+25x+12=\frac{9}{4}x^2+18x+36$

Move everything to one side to get a quadratic:

$\displaystyle-\frac{1}{4}x^2+7x-24=0$

Solving using the quadratic formula:

A quadratic in $ax^2+bx+c$ has real solutions $\displaystyle x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$ . In $\displaystyle-\frac{1}{4}x^2+7x-24$ , assign values:

$\displaystyle \\a=-\frac{1}{4}\\b=7\\c=-24$

Solving yields:

$\displaystyle\\x=\frac{-7\pm \sqrt{7^2-4\left(-\frac{1}{4}\right)\left(-24\right)}}{2\left(-\frac{1}{4}\right)}\\\\x=\frac{-7\pm \sqrt{25}}{-\frac{1}{2}}\\\\\begin{cases}x=\frac{-7+5}{-0.5}=\frac{-2}{-0.5}=\boxed{4}\\x=\frac{-7-5}{-0.5}=\frac{-12}{-0.5}=24 \:(\text{Extraneous})\end{cases}$

Only $x=4$ works when plugged in the original equation. Therefore, $x=24$ is extraneous and the only solution is $\boxed{x=4}$

4 0

2 years ago

Please help with this question

alisha [4.7K]

Yes because 4x3^x =12^x since the coefficient is added to the answer because it is in the 3.

3 0

3 years ago