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kaheart [24]
3 years ago
5

The right triangle shown has angles X, Y, and Z and side lengths a, b, and

Mathematics
1 answer:
laiz [17]3 years ago
4 0
So attached is a picture of the triangle you are talking about and listed under are the choices:

A.) Cos Z=b/c 
B.) Sin X=c/b 
C.) Tan X=b/a 
<span>D.) Tan Z=a/b
</span>
The answer would then be B. SinX = c/b.

Just remember SOH CAH TOA:

Sinθ=  Opposite         Cosθ =    Adjacent             Tanθ=   Opposite
         Hypotenuse                   Hypotenuse                        Adjacent

Using the triangle in the scenario, you just need to identify which side is which. 

Given m∠Z
Adjacent = b
Opposite = a
Hypotenuse = c

SinZ=  a         CosZ = b             TanZ= a 
            c                      c                        b

Given m∠X:

Adjacent = b
Opposite = a
Hypotenuse = c

SinX= <u> b </u>        CosX =<span><u> a </u></span>            TanX=<span><u> b </u></span>
            c                      c                        a

So the answer is B. 

Attached is a picture of how I assigned the sides depending on the angle used.

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