Part 1:
You have the correct answer. You multiply the probability of getting red (6/15) by the probailitiy of getting red (6/15) to get 36/225 which reduces to 4/25
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Part 2:
This is also correct. Nice work. You multiply the probability of getting black (9/15) with the probability of getting red (6/15) to get 54/225 = 6/25
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Part 3:
The probability of picking a black checker is 9/15. If a replacement is made, then the probability of picking another black checker is also 9/15. So,
(9/15)*(9/15) = 81/225 = 9/25
Answer: 9/25
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Part 4:
The probability of rolling a 6 is 1/6. The probability of rolling a 3 is 1/6 as well. This is because there is only one side with this label out of 6 total. Multiply the probabilities
(1/6)*(1/6) = 1/36
Answer: 1/36
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Part 5:
It is impossible to roll a 7 on the six sided cube because the highest number is 6. Therefore the overall probability is 0
Answer: 0
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Part 6:
There are 3 outcomes we want (rolling a 1,2, or 3) out of 6 total. So the probability of rolling a 1,2 or 3 is 3/6 = 1/2. Similarly, the probability of rolling a 4, 5 or 6 is 3/6 = 1/2 as well.
Multiplying the probabilities gives
(1/2)*(1/2) = 1/4
Answer: 1/4
5. The graph of g(x) is narrower. Both graphs open upward. The vertex of g(x), (0,10), is translated 10 units up from the vertex of f(x) at (0,0)
6. The graph of g(x) is wider. Both graphs open upward. The vertex of g(x), (0,-3) is translated 3 units down from the vertex of f(x) at (0,0)
7.The graph of g(x) is narrower. g(x) opens downward and f(x) opens upward. The vertex of g(x), (0,8) is translated 8 units up from the vertex of f(x) at (0,0).
8. The graph of g(x) is wider. g(x) opens downward and f(x) opens upward. The vertex of g(x), (0,1/4) is translated 1/4 units up from the vertex of f(x) at (0,0).
9. A. h1(t)=-16t^2+400 h2(t)= -16t^2+1600
9. B The graph of h2 is a vertical translation of the graph of h1 : 1200 units up.
9. C sandbag dropped from 400 ft: 5 s
sandbag dropped from 1600 ft: 10 s
Answer:
I DON'T KNOW AT ALL
Step-by-step explanation:
CAN SOMEONE PLZ HELP ME WITH MY WORK
The order of these statements are CADB
