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icang [17]
3 years ago
10

Please help me on this ASAP am I right ?

Mathematics
2 answers:
Paraphin [41]3 years ago
8 0

Answer:

No, you would graph the y-intercept, you do not graph the m-value (slope). The slope value is the rate that the y-value increases per unit of x. This is how you graph your line from the y-intercept

mash [69]3 years ago
7 0

Answer:

No you are incorrect. <em>The correct answer is (y - intercept) b = -4</em>

Step-by-step explanation:

You need to plot the y - intercept first so that you can create the line using the slope starting from the y - intercept. You can't plot the line unless you first plot a point on the line which would be the y - intercept or -4 THEN from there you use the slope to create the line.

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Write a linear function f with the values f(10)=5 and f(2)=-3
Nutka1998 [239]

Answer:

f(x)=x-5

Step-by-step explanation:

step 1

Find the slope m

The formula to calculate the slope between two points is equal to

m=\frac{y2-y1}{x2-x1}

we have the ordered pairs

(10,5) and (2,-3)

substitute the values

m=\frac{-3-5}{2-10}

m=\frac{-8}{-8}

m=1

step 2

Find the equation of the line in slope intercept form

f(x)=mx+b

we have

m=1

point\ (10,5)

substitute and solve for b

5=(1)(10)+b

5=10+b

b=-5

The linear function is equal to

f(x)=x-5

3 0
3 years ago
Is -2 a whole number
Harlamova29_29 [7]

Answer:

Whole numbers are all natural numbers including 0 e.g. 0, 1, 2, 3, 4… Integers include all whole numbers and their negative counterpart e.g. … -4, -3, -2, -1, 0,1, 2, 3, 4,… Where a and b are both integers.

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
To get the correct color, Johan mixed 3 1/4 quarts of white paint, 1 2/4 quarts of blue paint,2 3/4 quarts of green paint. How m
aivan3 [116]
I hope this helps you understand how to do the problem.

8 0
3 years ago
A person 6ft tall stands 10ft from point P directly beneath a lantern hanging 30 ft above the ground. The lantern start to fall,
xxMikexx [17]

Answer:

\frac{dL}{dt}=30 \frac{ft}{s}

Step-by-step explanation:

In order to solve this it is always a good idea to start by drawing a diagram of the situation (See attached picture).

From the diagram we can see that we are dealing with similar triangles. We can use similar triangles to build an equation that relates the length of the shadow with the height of the lamp, so we get:

\frac{L}{6}=\frac{10+L}{h}

the height of the lamp can be found by subtracting the 16t^{2} distance the lamp falls in a given time t from the original 30ft the lamp was located at.

So the equation will now lok like this:

\frac{L}{6}=\frac{10+L}{30-16t^{2}}

So now we can solve the equation for L, we can start by multiplying by the LCD SO WE GET:

L(30-16t^{2})=6(10+L)

next, we can distribute the right side of the equation so we get:

L(30-16t^{2})=60+6L

and subtract 6L from both sides so we get:

L(30-16t^{2})-6L=60

and factor L, so we get:

L(30-16t^{2}-6)=60

and solve for L:

L=\frac{60}{24-16t^{2}}

now, we can differentiate this equation by using the chain rule, so we get:

dL=-\frac{60}{(24-16t^{2})^{2}}(-32t)dt

which can be simplified to:

\frac{dL}{dt}=\frac{1920t}{(24-16t^{2})^{2}}

and now we can substitute t for 1s so we get:

\frac{dL}{dt}=\frac{1920(1)}{(24-16(1)^{2})^{2}}

\frac{dL}{dt}=30 \frac{ft}{s}

7 0
3 years ago
Simplify (√3 − √2)^2
Umnica [9.8K]

(\sqrt{3} -\sqrt{2} )^2=\sqrt{3}^2-2\times\sqrt{3}\times\sqrt{2}+\sqrt{2}^2=3-2\sqrt{6} +2=5-2\sqrt{6}

4 0
3 years ago
Read 2 more answers
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