All categories

3 years ago

Please help me on this ASAP am I right ?

Mathematics

2 answers:

Paraphin [41]3 years ago

8 0

Answer:

No, you would graph the y-intercept, you do not graph the m-value (slope). The slope value is the rate that the y-value increases per unit of x. This is how you graph your line from the y-intercept

mash [69]3 years ago

7 0

Answer:

No you are incorrect. <em>The correct answer is (y - intercept) b = -4</em>

Step-by-step explanation:

You need to plot the y - intercept first so that you can create the line using the slope starting from the y - intercept. You can't plot the line unless you first plot a point on the line which would be the y - intercept or -4 THEN from there you use the slope to create the line.

You might be interested in

The Trapezoidal rule Tn on the interval [0,5) will be exact for

igomit [66]

Answer:

degree 1

Step-by-step explanation:

The trapezoidal rule is exact when the second derivative is zero. This occurs when the polynomial is degree one or less

5 0

3 years ago

What value of x makes the equation 3^(x-5)=27^(x+4) true?

SVEN [57.7K]

Answer:

The attached file contains the solution to the question

7 0

2 years ago

Please help me I am stressed it is ratio tables

Oduvanchick [21]

Answer:

1/2/3/4/5/32

3/6/9/12/15/96

1/2/3/4/5/12

8/16/24/32/96

2/4/6/8/10/12

3/6/9/12/15/18

Step-by-step explanation:

ratios are basically in "#:#" form. then put that in a table. remember that for each one of one thing, it is equivalent to another thing. it might be easy to count it. good luck

5 0

3 years ago

What is the value of x in the equation ln (x + 6) – ln (2x – 1) = 1?

Alexandra [31]

Answer:

this is a no solution problem, nothing could sub for x and make this true

7 0

3 years ago

James has 14{,}500\text { g}14,500 g14, comma, 500, start a text, space, g, end text of sand in his sandbox. He brings home anot

mariarad [96]

Question:

James has 14,500g of sand in his sandbox. He brings home another 7,400g of sand from the beach to add to his sandbox. How many kilograms of sand does James have in his sandbox now?

Answer:

The quantity of sandbox James has is 21.9kg

Step-by-step explanation:

Given

Initial quantity of sandbox = 14,500 g

Additional quantity = 7,400 g

Required

Total quantity of sandbox in kg

Tp get the total quantity of sandbox, we simply add in the initial and additional quantity of sandbox together;

This is represented mathematically as follows;

Total = Initial Quantity + Additional Quantity

Total = 14,500 g + 7,400 g

Total = 21,900 g

But the question says the answer should be in kg

1000 g is equivalent to 1 kg

21,900 g will be equivalent to $\frac{21,900}{1,000} kg$

$21,900g = \frac{21,900}{1,000} kg$

$21,900g = 21.9 kg$

Hence, the quantity of sandbox James has is 21.9kg

7 0

3 years ago