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3 years ago

Please help me on this ASAP am I right ?

Mathematics

2 answers:

Paraphin [41]3 years ago

8 0

Answer:

No, you would graph the y-intercept, you do not graph the m-value (slope). The slope value is the rate that the y-value increases per unit of x. This is how you graph your line from the y-intercept

mash [69]3 years ago

7 0

Answer:

No you are incorrect. The correct answer is (y - intercept) b = -4

Step-by-step explanation:

You need to plot the y - intercept first so that you can create the line using the slope starting from the y - intercept. You can't plot the line unless you first plot a point on the line which would be the y - intercept or -4 THEN from there you use the slope to create the line.

You might be interested in

A. ASA Postulate B. HL Theorem C.AAS Theorem D. SAS Postulate

TiliK225 [7]

Answer:

your answer will be B. HL Theorem 

Step-by-step explanation:

hope it helps you...

4 0

3 years ago

Suppose that f: R --> R is a continuous function such that f(x +y) = f(x)+ f(y) for all x, yER Prove that there exists KeR su

Pachacha [2.7K]

<h2>Answer with explanation:</h2>

It is given that:

f: R → R is a continuous function such that:

$f(x+y)=f(x)+f(y)------(1)$ ∀ x,y ∈ R

Now, let us assume f(1)=k

Also,

f(0)=0

( Since,

f(0)=f(0+0)

i.e.

f(0)=f(0)+f(0)

By using property (1)

Also,

f(0)=2f(0)

i.e.

2f(0)-f(0)=0

i.e.

f(0)=0 )

Also,

f(2)=f(1+1)

i.e.

f(2)=f(1)+f(1) ( By using property (1) )

i.e.

f(2)=2f(1)

i.e.

f(2)=2k

Similarly for any m ∈ N

f(m)=f(1+1+1+...+1)

i.e.

f(m)=f(1)+f(1)+f(1)+.......+f(1) (m times)

i.e.

f(m)=mf(1)

i.e.

f(m)=mk

Now,

$f(1)=f(\dfrac{1}{n}+\dfrac{1}{n}+.......+\dfrac{1}{n})=f(\dfrac{1}{n})+f(\dfrac{1}{n})+....+f(\dfrac{1}{n})\\\\\\i.e.\\\\\\f(\dfrac{1}{n}+\dfrac{1}{n}+.......+\dfrac{1}{n})=nf(\dfrac{1}{n})=f(1)=k\\\\\\i.e.\\\\\\f(\dfrac{1}{n})=k\cdot \dfrac{1}{n}$

Also,

when x∈ Q

i.e. $x=\dfrac{p}{q}$

Then,

$f(\dfrac{p}{q})=f(\dfrac{1}{q})+f(\dfrac{1}{q})+.....+f(\dfrac{1}{q})=pf(\dfrac{1}{q})\\\\i.e.\\\\f(\dfrac{p}{q})=p\dfrac{k}{q}\\\\i.e.\\\\f(\dfrac{p}{q})=k\dfrac{p}{q}\\\\i.e.\\\\f(x)=kx\ for\ all\ x\ belongs\ to\ Q$

(

Now, as we know that:

Q is dense in R.

so Э x∈ Q' such that Э a seq belonging to Q such that:

$\to x$ )

Now, we know that: Q'=R

This means that:

Э α ∈ R

such that Э sequence $a_n$ such that:

$a_n\ belongs\ to\ Q$

and

$a_n\to \alpha$

$f(a_n)=ka_n$

( since $a_n$ belongs to Q )

Let f is continuous at x=α

This means that:

$f(a_n)\to f(\alpha)\\\\i.e.\\\\k\cdot a_n\to f(\alpha)\\\\Also\\\\k\cdot a_n\to k\alpha$

This means that:

$f(\alpha)=k\alpha$

This means that:

f(x)=kx for every x∈ R

4 0

3 years ago

What is 8/10 divided by 1 5/6

yulyashka [42]

The answer is 0.43 that is what i got

7 0

3 years ago

Read 2 more answers

On a fishing excursion, jeannie keeps 1/4 of the fish she catches and releases the remainder of the fish back into the lake. if

postnew [5]

To find 1/3 of 3/4 we divide the fraction by 3 which is equal to 1/4 or alternatively we can multiply the denominator by 3 which gives us 3/12 (1/4=3/12)
So 3/12 of the realesed fish are trout

To find 2/3 of 1/4 we need to first divide 1/4 by 3 which is equal to multiplying the denominator times 3 which gives us 1/12 and then we multiply by 2 which gives us 2/12
So 2/12 of the kept fish are trout

To find the total amount we add 2/12 and 3/12
3/12+2/12= 5/12

ANSWER:
5/12 of the fish she catches are trout

7 0

3 years ago

Plz help me thank you

murzikaleks [220]

Slope intercept form is y = mx + b where m is slope and b is y intercept.

The line crosses the y axis at y = 4

The slope is 4/3

So the answer is y = (4x/3) + 4

5 0

3 years ago