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3 years ago

Please help me on this ASAP am I right ?

Mathematics

2 answers:

Paraphin [41]3 years ago

8 0

Answer:

No, you would graph the y-intercept, you do not graph the m-value (slope). The slope value is the rate that the y-value increases per unit of x. This is how you graph your line from the y-intercept

mash [69]3 years ago

7 0

Answer:

No you are incorrect. <em>The correct answer is (y - intercept) b = -4</em>

Step-by-step explanation:

You need to plot the y - intercept first so that you can create the line using the slope starting from the y - intercept. You can't plot the line unless you first plot a point on the line which would be the y - intercept or -4 THEN from there you use the slope to create the line.

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What is the square root of 139

VladimirAG [237]

Square root of 139:
√139 = 11.78983

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3 years ago

So this has to do with permutations and honestly I need an explanation on how I can figure these out.

AnnZ [28]

Well, the answer quite simple ....there are 4! ways to arrange these numbers...and as 4! = 4*3*2*1 = 24

hence 24 is the correct answer....

u can also remember it by theorem of multiplication as.....in first place (I.e. first code can be any no. out of 4,5,2&7 ....so 4*.....

as first place is acquired by a certain no. that leaves three no. to fill third place and when third place I'd occupied it leaves 2 numbers to fill second place and lastly only one no. to fill the last place .....so it's result will be like 4*3*2*1.

I know this is pretty much confusing ....but still I tried my best....

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4 years ago

Alicia works out 7.5+4.8 in her head

Usimov [2.4K]

Answer:

12.3

Step-by-step explanation:

8 0

3 years ago

NEED HELP Find values for a, b, c, and d so that the following matrix product equals the 2X2 identity matrix. Explain or show ho

ehidna [41]

We want to find the values of a, b, c, and d such that the given matrix product is equal to a 2x2 identity matrix. We will solve a system of equations to find:

b = 1
a = -1
c = -2
d = -1

<h3>Presenting the equation:</h3>

Basically, we want to solve:

$\left[\begin{array}{cc}-1&2\\a&1\end{array}\right]*\left[\begin{array}{cc}b&c\\1&d\end{array}\right] = \left[\begin{array}{cc}1&0\\0&1\end{array}\right]$

The matrix product will be:

$\left[\begin{array}{cc}-b + 2&-c + 2d\\a*b + 1&a*c + d\end{array}\right]$

Then we must have:

-b + 2 = 1

This means that:

b = 2 - 1 = 1

b = 1

We also need to have:

a*b + 1 = 0

we know the value of b, so we just have:

a*1 + b = 0

a = -1

Now the two remaining equations are:

-c + 2d = 0

a*c + d = 1

Replacing the value of a we get:

-c + 2d = 0

-c + d = 1

Isolating c in the first equation we get:

c = 2d

Replacing that in the other equation we get:

-(2d) + d = 1

-d = 1

d = -1

Then:

c = 2d = 2*(-1) = -2

c = -2

So the values are:

b = 1
a = -1
c = -2
d = -1

If you want to learn more about systems of equations, you can read:

brainly.com/question/13729904

4 0

3 years ago

12 midnight ....... tell me

docker41 [41]

Answer:

I am not getting your question .

5 0

3 years ago

Read 2 more answers