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2 years ago

The population of rabbits on an island is growing exponentially. In the year 2001,

Mathematics

2 answers:

chubhunter [2.5K]2 years ago

7 0

Answer: 3273

Step-by-step explanation:

Alexxandr [17]2 years ago

6 0

I think the answer is 666.

2050-940=1110

1110/5=222

222x3=666

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2x=90 3y-2x=90 Please tell me work

svp [43]

90 divided by 2= 45 so x=45
2•45=90
So, for the next one y=60 because 90+90=180
3•60-2•45=90

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3 years ago

What is the solution to the system of equations? 6x+2y=6 7x+3y=5

Stells [14]

The answer is (2,-3)

4 0

2 years ago

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What is the solution to the system of equations graphed below? y=-4x + 33 y=5/3x-1

Black_prince [1.1K]

Answer:

x = 6

y = 9

This is the correct answer. Not satisfied? Check out this answer expert verified answer of the same question but with a step-by-step explanation. This answer is just a simple version of rocioo's correct answer.

Expert Verified Answer (of this same question but with a step-by-step explanation):

This is the link to rocioo's answer. brainly.com/question/13675950

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3 years ago

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When a bactericide is added to a nutrient broth in which bacteria are growing, the bacteria population continues to grow for a

baherus [9]

Answer:

a) 1296 bacteria per hour

b) 0 bacteria per hour

c) -1296 bacteria per hour

Step-by-step explanation:

We are given the following information in the question:

The size of the population at time t is given by:

$b(t) = 9^6 + 6^4t-6^3t^2$

We differentiate the given function.

Thus, the growth rate is given by:

$\displaystyle\frac{db(t)}{dt} = \frac{d}{dt}(9^6 + 6^4t-6^3t^2)\\\\= 6^4-2(6^3)t$

a) Growth rates at t = 0 hours

$\displaystyle\frac{db(t)}{dt} \bigg|_{t=0}= 6^4-2(6^3)(0) = 1296\text{ bacteria per hour}$

b) Growth rates at t = 3 hours

$\displaystyle\frac{db(t)}{dt} \bigg|_{t=3}= 6^4-2(6^3)(3) = 0\text{ bacteria per hour}$

c) Growth rates at t = 6 hours

$\displaystyle\frac{db(t)}{dt} \bigg|_{t=6}= 6^4-2(6^3)(6) = -1296\text{ bacteria per hour}$

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3 years ago

Elizabeth is going to invest $480 and leave it in an account for 8 years. Assuming the interest is compounded continuously, what

zzz [600]

Answer:

4.2

Step-by-step explanation:

took a bullet for the team

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2 years ago