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Amanda [17]
3 years ago
10

“Sarah made the trip in 10 hours, but it only took Alice 8 hours to make the same trip. Find Sarah and Alice's rates if Alice's

rate was 3 mph more than Sarah's rate. “ i don’t know how to solve this.
Mathematics
1 answer:
Mnenie [13.5K]3 years ago
4 0

Answer:

I belive it would be 28 mph.


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Er the given circle.
nataly862011 [7]

Answer:

Step-by-step explanation:

answers

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3 0
3 years ago
If 75% of x is 150, what is the value of x?
vagabundo [1.1K]
I'm not sure if this is correct but you would put it into an equation while you solve for X. so 0.75x=150  or equivalently would be like  (3/4)x=150 Then after that you would divide both sides by 0.75 or 3/4 
7 0
3 years ago
The frequency table shows a set of data collected by a doctor for adult patients who were diagnosed with a strain of influenza.
Alexxx [7]

Answer:

The answer would be the second plot

Step-by-step explanation:

The frequency table show how many sick patients there are in a single age range. In the first two plots, the total dots between numbers 24, 25, 26, 27, 28, and 29 add up to 3, and the other 2 plots do not, so those are not correct.

When we add up the total of dots from ages 30-34 on the first plot, there are only 4 sick patients. On the second graph, there are 6 total patients in that age range. Therefore, the dot plot that corresponds with the frequency table is the second one.

7 0
4 years ago
Read 2 more answers
Pls help! given: -2(x-4)=2x+12 Prove: x=-1
nata0808 [166]

Answer:

X= -1

Step-by-step explanation:

In pic

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7 0
2 years ago
Find the oth term of the geometric sequence 5,--25, 125,
Genrish500 [490]

Given the geometric progression below

5,-25,125,\ldots

The nth term of a geometric progression is given below

T_n=ar^{n-1},\begin{cases}a=\text{first term} \\ r=\text{common ratio}\end{cases}

From the geometric progression, we can deduce the following

\begin{gathered} T_1=a=5 \\ T_2=ar=-25 \\ T_3=ar^2=125 \end{gathered}

To find the value of r, we will take ratios of two consecutive terms

\begin{gathered} \frac{T_2}{T_1}=\frac{ar}{a}=\frac{-25}{5} \\ \Rightarrow r=-5 \end{gathered}

To find the 9th term of the geometric, we will have that;

\begin{gathered} T_9=ar^8=5\times(-5)^8=5\times390625 \\ =1953125 \end{gathered}

Hence, the 9th term of the geometric progression is 1953125

8 0
1 year ago
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