Assume that the amount needed from the 5% solution is x and that the amount needed from the 65% solution is y.
We are given that, the final solution should be 42 ml, this means that:
x + y = 42 ...........> equation I
This can also be written as:
x = 42-y .......> equation II
We are also given that the final concentration should be 45%, this means that:
5% x + 65% y = 45% (x+y)
0.05x + 0.65y = 0.45(x+y)
We have x+y = 42 from equation I, therefore:
0.05x + 0.65y = 0.45(42)
0.05x + 0.65y = 18.9 .........> equation III
Substitute with equation II in equation III as follows:
0.05x + 0.65y = 18.9
0.05(42-y) + 0.65y = 18.9
2.1 - 0.05y + 0.65y = 18.9
0.6y = 18.9 - 2.1
0.6y = 16.8
y = 28 ml
Substitute with y in equation II to get x as follows:
x = 42-y
x = 42 - 28
x = 14 ml
Based on the above calculations:
amount of 5% solution = x = 14 ml
amount of 65% solution = y = 28 ml
The correct choice is:
The teacher will need 14 mL of the 5% solution and 28 mL of the 65% solution.
Answer: a is 200e^.07t the answer to b is 402.75
Step-by-step explanation:
Because I got it wrong and it showed me the correct answers
Answer:
The answer to your question is:
m = length of the smaller bed = 17 ft
l = length of the larger bed = 25 ft
Step-by-step explanation:
Data
A1 + A2 = 914
A1 - A2 = 336
A1 = l²
A2 = m²
Process
l² + m² = 914
l² - m² = 336
l² = 336 + m²
(336 + m²) + m² = 914
336 + 2m² = 914
2m² = 914 - 336
2m² = 578
m² = 578 / 2
m² = 289
m = 17 ft
l² = 336 + 289
l² = 625
l = 25 ft
D. 9x-2
This is equivalent to the expression.
hope this helps!
