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DiKsa [7]
3 years ago
12

Need answer asap ..................................

Mathematics
1 answer:
erica [24]3 years ago
4 0
Yup it’s 66 that’s right hrhdndjdhehdhdbddhdbhdhd
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What is the area of a square with a side of 8x^7 y^3
sukhopar [10]
Area of a square with side s is \sf{s^2}

In your question, the side or s is: \sf{8x^7y^3}

And so the area of a square with that side length would be:

\sf{(8x^7y^3)^2}

And using this formula: \sf{(a^b)^c =a^{b\times c}}

We get that the area is:

\sf{(8x^7y^3)^2 = 8^2 x^{7\times 2} y^{3\times 2}}

And simplifying that we get the final answer as:

\huge{\boxed{\bf{Area=64x^{14}y^{6}}}}
4 0
3 years ago
Please help!! ill give BRAINLIEST!!!
docker41 [41]
1. Rhombus
2. Rectangle
3. Trapezoid
4. False
5. True
6. False
7. True
8. True
7 0
3 years ago
What is the answer? <br> May you please help me on this<br> Plsss asapp
sergey [27]

Answer:

i believe its c

Step-by-step explanation:

6 0
2 years ago
Simplify (-63) divided by (-9)
Charra [1.4K]

Answer:

7

Step-by-step explanation:

-63/-9

7

6 0
3 years ago
What is the answer for the equation above
Dimas [21]
Add 5+3 raised to the 2nd which givea u (8)^2
do the 5 squared which gives u 1+25-23

evaluate 8^2=64
subtract the sum u should get 64 over 3, 21 and 1/3 or 21.3333333 repeating
3 0
3 years ago
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