What picture theres no pic
Answer:
20 gallons were used from the tank with the octane rating of 80.
Step-by-step explanation:
Given : One tank of gasoline has an octane rating of 140 and another tank of gasoline has an octane rating of 80. To obtain a mixture of 60 gallons with an octane rating of 120.
To find : How many gallons should be used from the tank with the octane rating of 80?
Solution : Let x be the volume of gas whose octane rating is 140 and
y be the volume of gas whose octane rating is 80.
Then, we form the equation as:
(1) 

or
.........[3]
(2) 
Now multiply equation (2) by 4
...........[4]
Subtract (4) from (3)



Put x in equation [4] we get,





Therefore, x=40 and y=20
So, 20 gallons were used from the tank with the octane rating of 80.
Answer:
2·(a^2 + b^2) = (a + b)^2
2·a^2 + 2·b^2 = a^2 + 2·a·b + b^2
a^2 + b^2 = 2·a·b
a^2 - 2·a·b + b^2 = 0
(a - b)^2 = 0
a = b
I believe there is only one outlier (shown in this picture) mostly because it is the farthest from this dotted mess