In ΔPQR, the measure of ∠R=90°, QR = 61 feet, and RP = 90 feet. Find the measure of ∠P to the nearest degree.

Mathematics

2 answers:

julia-pushkina [17]3 years ago

7 0

Step-by-step explanation:

given= in triangle PQR,<R=90⁰ QR=61 FEET RP=90 FEET

by using pythagoras therom ;

(hypotenuse)²=(side1)² +(side2)²

(PQ)²=(PR)²+(QR)²

(PQ)²=(90)² + (61)²

(PQ)²=8100 + 3721

(PQ)²=11821

TAKING SQUARE ROOTS ON BOTH SIDES, WE GET;

PQ= 108 feet

<P = thita

sin ⁰ = opposite/hypotenuse

sin⁰ =QR/PQ

SIN⁰ =61/108

SIN⁰ =0.56

there amgle P measures 0.56 degree

qwelly [4]3 years ago

4 0

Answer:

Step-by-step explanation:

its right

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