I guess this is a geometric series:
a6 = a1 * r^5 so
a1 = 0.03125 / 0.5^5
= 1 answer
Answer:
The area of one trapezoidal face of the figure is 2 square inches
Step-by-step explanation:
<u><em>The complete question is</em></u>
The point of a square pyramid is cut off, making each lateral face of the pyramid a trapezoid with the dimensions shown. What is the area of one trapezoidal face of the figure?
we know that
The area of a trapezoid is given by the formula
where
b_1 and b-2 are the parallel sides
h is the height of the trapezoid (perpendicular distance between the parallel sides)
we have
substitute the given values in the formula
We will find the answer using the second law of motion i.e. Force is equal to the product of mass and acceleration.
Where,
- F is force
- M is mass
- A is acceleration
In our case,
Let's solve for M ~
<em>Thus, The mass of object is 36.36 </em><em>grams</em><em>.</em><em>.</em><em>.</em><em>~</em>
Answer:
125.6
Step-by-step explanation:
all you have to do is multiple the 3.14 with 40 cm to get 125.6 cm
Answer:
3 metres
Step-by-step explanation:
Let the width of the pathway be x
Area: (9+2x)(4+2x)
36 + 8x + 18x + 4x²
4x² + 26x + 36
Increased area is 150:
4x² + 26x + 36 = 150
4x² + 26x - 114 = 0
2x² + 13x - 57 = 0
2x² + 19x - 6x - 57 = 0
x(2x + 19) - 3(2x + 19) = 0
(x - 3)(2x + 19) = 0
x = 3, x = -19/2