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Hatshy [7]
3 years ago
13

Round 6.362 cg to 3 significant figures: ____ cg 6.36 6.40 6.37

Mathematics
2 answers:
elena-14-01-66 [18.8K]3 years ago
8 0

Answer:

6.36

Step-by-step explanation:

aksik [14]3 years ago
3 0
I think it should be 6.36
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Amelio has 6 more nickels than dimes, and the total value is $2.10. how many nickels does he have?
Nezavi [6.7K]
Amelio have 18 Nickels and 12 dimes!!

2.10−(6×0.05)−(12×0.10)−(12×0.05)= 0
6 0
3 years ago
A space shuttle is made
zaharov [31]

Answer:

The actual space shuttle is 66 feet tall

Step-by-step explanation:

scale of 1 inch : 12 feet represent the scale of a space shuttle.

It means it has a representation of 1 inch on paper then actual = 12 feet.

But then if the paper(model) changes to 5.5 inches. The actual representation on land will be

Let me write out the equation

1 inch = 12 feet

5.5 inch =( 5.5 inch *12 feet)/1 inch

5.5 Inch= 5.5 * 12 feet

5.5 inch = 66 feet

8 0
3 years ago
For a certain​ candy, 20​% of the pieces are​ yellow, 15​% are​ red, 20​% are​ blue, 20​% are​ green, and the rest are brown. ​a
OLEGan [10]

Answer:

Step-by-step explanation:

Based on the question we are given the percentages of each of the types of candies in the bag except for brown. Since the sum of all the percentages equals 75% and brown is the remaining percent then we can calculate that brown is (100-75 = 25%) 25% of the bag. Now we can show the probabilities of getting a certain type of candy by placing the percentages over the total percentage (100%).

  • Brown: \frac{25}{100}
  • Yellow or Blue: \frac{20}{100} +\frac{20}{100} = \frac{40}{100}  ....add the numerators
  • Not Green:  \frac{80}{100}.... since the sum of all the rest is 80%
  • Stiped:  \frac{25}{100} .... there are 0 striped candies.

Assuming the <u><em>ratios/percentages</em></u> of the candies stay the same having an infinite amount of candy will not affect the probabilities. That being said in order to calculate consecutive probability of getting 3 of a certain type in a row we have to multiply the probabilities together. This is calculated by multiplying the numerators with numerators and denominators with denominators.

  • 3 Browns: \frac{25*25*25}{100*100*100} = \frac{15,625}{1,000,000} = \frac{1.5625}{100}

  • the 1st and 3rd are red while the middle is any. We multiply 15% * (total of all minus red which is 85%) * 15% like so.

\frac{15*85*15}{100*100*100} = \frac{19,125}{1,000,000} = \frac{1.9125}{100}

  • None are Yellow: multiply the percent of all minus yellow three times.

\frac{80*80*80}{100*100*100} = \frac{512,000}{1,000,000} = \frac{51.2}{100}

  • At least 1 green: multiply the percent of green by 100% twice, since the other two can by any

\frac{20*100*100}{100*100*100} = \frac{200,000}{1,000,000} = \frac{20}{100}

4 0
3 years ago
PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!! I CANNOT RETAKE THIS!!
alex41 [277]

the correct answer should be (b) 6 is extraneous.

If you look at the second row of the solution you see (x-6) as a factor in one of the denominators. That's a problem: if 6 were a solution this denominator would become 0. But denominators being 0 is bad (undefined), so while 6 comes out of the algebraic manipulation as a solution, it is invalid, or extraneous.

-3 is a fine solution.

6 0
3 years ago
Read 2 more answers
Draw 3 rows of 10 oranges.
statuscvo [17]
We cannot help you with that, sorry
8 0
3 years ago
Read 2 more answers
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