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elena-s [515]
3 years ago
5

There are 36 math books and 9 reading books. What is the ratio of the total number of books to the number of math books? Remembe

r to simplify your answer.
Mathematics
1 answer:
brilliants [131]3 years ago
8 0

Answer:

\frac{4}{5}

Step-by-step explanation:

so its 36+9 = 45

36/45=4/5

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Assume that the weight loss for the first month of a diet program varies between 6 pounds and 12 pounds, and is
swat32

Answer:

1/3

Step-by-step explanation:

Range of data set: 12 - 6 = 6

Given that there is a uniform distribution:

P(6<x<7) = 1/6

P(7<x<8) = 1/6

P(8<x<9) = 1/6

P(9<x<10) = 1/6

P(10<x<11) = 1/6

P(11<x<12) = 1/6

where x is weight loss

Probability that weight loss is more than 10 pounds:

P(10<x<11) + P(11<x<12) = 1/6 + 1/6 = 1/3

3 0
4 years ago
Answer and explanation plz ???
Nutka1998 [239]

Answer:

25

Step-by-step explanation:

Formula

2xy + 1

Givens

x = 3

y = 4

Solve

2*(3)*(4) + 1

24 + 1

25

7 0
3 years ago
The deck of a bridge is suspended 275 feet above a river. If a pebble falls off the side of the bridge, the height, in feet, of
Ivenika [448]

Answer:

Our equation for the height is:

y(t) = 275 - 16*t^2.

a) To find the average velocity between two times, t1 and t2, (where t2 > t1) the equation is:

AV = \frac{y(t2) - y(t1)}{t2 - t1}

Then:

i) t1 = 4s, t2 = 4s + 0.1s = 4.1s

The average velocity is:

AV = \frac{(275 - 16*4.1^2) - (275 - 16*4^2)}{4.1 - 4} = \frac{16(4^2 - 4.1^2)}{0.1} = -129.6

And the units will be ft/s, so the average speed is:

-129.6 ft/s

The minus sign is because te pebble is falling down.

ii)  t1 = 4s, t2 = 4s + 0.05s = 4.05s

The average velocity is:

AV = \frac{(275 - 16*4.05^2) - (275 - 16*4^2)}{4.05 - 4} = \frac{16(4^2 - 4.05^2)}{0.05} = -128.8

So the average speed is -128.9 ft/s

iii)  t1 = 4s, t2 = 4s + 0.01s = 4.01s

The average speed is:

AV = \frac{(275 - 16*4.01^2) - (275 - 16*4^2)}{4.01 - 4} = \frac{16(4^2 - 4.01^2)}{0.01} = -128.16

The average speed is -128.16 ft/s.

b) The instantaneous velocity of the pebble after 4 seconds can be obtained by looking at the velocity equation, that is the derivative of the height equation.

v(t) = dy(t)/dt.

v(t) = -2*16*t + 0

Then the velocity at t = 4s is:

v(4s) = -32*4 = -128

The instantaneous velocity at t = 4s is -128 ft/s.

3 0
3 years ago
determine the equation of the straight line which passes through the point 1 and 5 and is perpendicular to the line 3x + y is eq
xenn [34]

The straight line is perpendicular to y = -3x + 4.

Therefore, the gradient of the straight line must be 3.

The equation of the straight line is y = 3x + 2.

7 0
3 years ago
Transversal relations
Shalnov [3]

Answer:

The answer is 75

Step-by-step explanation:

By way of parallelism

x + 15 = 90 \\ x = 75

7 0
3 years ago
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