Answer:
A) -sqrt(3)/3
Step-by-step explanation:
If you know your unit circle (attached), 11pi/6 has the value of (sqrt(3)/2,-1/2), where the coords are (cosine, sine).
Tangent is sine/cosine:
(-1/2)/(sqrt(3)/2)
We can convert this to multiplication by miltiplying the reciprocal of sqrt(3)/2:
(-1/2)*(2/sqrt(3))
Multiplied out to:
-2/(2sqrt(3))
We have to rationalize this by multiplying the numerator and denominator by sqrt(3):
-2(sqrt(3))/2sqrt(3)(sqrt(3)
two of the same square roots multiplied together equals the number without the sqrt:
-2(sqrt(3))/2*3
we can factor out 2 from the numerator and denominator:
-sqrt(3)/3
Therefore, the answer is A
Answer:
x = 8
Step-by-step explanation:
8 minus 16 equals to a negative answer, resulting to -8.
The volume of the cylinder in discuss in which case, the radius of the cylinder is 3 inches and the height is inches is; V = 141.3in³.
<h3>What is the volume of the the described cylinder?</h3>
The cylinder in discuss according to the task content has radius, 3 inches and height, 5 inches.
Since the volume of a cylinder by convention is given as; V = πr²h
Therefore, the volume of the cylinder in discuss is;
V = π (3²)×5
V = 3.14 × 45
V = 141.3in³
Read more on volume of a cylinder;
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Answer:
$2,871.00
Step-by-step explanation:
Calculation:
First, converting R percent to r a decimal
r = R/100 = 8%/100 = 0.08 per year.
Solving our equation:
A = 1595(1 + (0.08 × 10)) = 2871
A = $2,871.00
The total amount accrued, principal plus interest, from simple interest on a principal of $1,595.00 at a rate of 8% per year for 10 years is $2,871.00.
6. 6th grade- go to the two columns above $600, which is about 8 students in the first column and 5 students in the 2nd. 8 + 5 = 13, so 13 students in 6th grade earned $600 or more.
7th grade- again, go to the columns above $600, which is about 7 students in the first column and about 3 in the 2nd column. 7 + 3 = 10, so 10 students in 7th grade earned $600 or more.
Do the same thing for #7, just follow the rows exactly as #6.
