Answer:
65 %
hope this helps
have good day :)
Step-by-step explanation:
Hello!
First of all, let's undo the square roots by squaring both sides.
6x+2=9x-8
We subtract 9x from both sides.
-3x+2=-8
We subtract 2 from both sides.
-3x= -10
We divide both sides by -3.
x=10/3
I hope this helps!
(y - 2) = (5/3)(x - 7) Is horizontal and contains.
I'm not sure that's the answer but I hope it helps you with something!!
I believe it to be 1 over 3 as 1 as the numerator and 3 as the denominator
Example: 2x+2y=8 and 3y+2x=6
Okay so u first want to put on of the equations into a y= form. So let's use 3y+2x=6. Subtract 2x from both sides. 3y=6-2x divide by 3. Y= 6-2/3x or y= -2/3x + 6. Now just plug this new equation in for Y since "y=" into the other equation.
2x + 2(-2/3x + 6) = 8.
Then you would distribute the 2 into the parenthesis and simplify to solve for x.
After you solve for x, plug x into one of the original equations to find y.
